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If the voltage dropped across a resistor increases by a factor of 10 the power dissipated by the resistor is?
The power dissipated by a resistor is given by the formula ( P = \frac{V^2}{R} ), where ( V ) is the voltage across the resistor and ( R ) is its resistance. If the voltage increases by a factor of 10, the new power can be expressed as ( P' = \frac{(10V)^2}{R} = \frac{100V^2}{R} = 100P ). Therefore, the power dissipated by the resistor increases by a factor of 100.
How is the power factor of an Electrodynamometer type wattmeter improved?
Power Factor of an electrodynamometer can be improved by connecting a large resistor in series with the current coil.
What method improve power factor?
The most common method of improving the power factor of a load is to connected a capacitor or capacitor bank, of appropriate reactive power (expressed in reactive volt amperes), in parallel with the load.
What is the function of a cement resistor?
A cement resistor is typically used as a power resistor (a resistor whose power rating is greater than 1 W).
At what level will typical resistors burn out?
A typical resistor will burn out when it dissipates power in excess of double its power dissipation rating for an extended period of time. The power dissipated by a resistor is equal to I2R or E2/R, where E = the voltage across the resistor I = the current through the resistor R = the resistance of the resistor
What is the power factor of pure resistor?
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If the voltage dropped across a resistor increases by a factor of 10 the power dissipated by the resistor is?
The power dissipated by a resistor is given by the formula ( P = \frac{V^2}{R} ), where ( V ) is the voltage across the resistor and ( R ) is its resistance. If the voltage increases by a factor of 10, the new power can be expressed as ( P' = \frac{(10V)^2}{R} = \frac{100V^2}{R} = 100P ). Therefore, the power dissipated by the resistor increases by a factor of 100.
How is the power factor of an Electrodynamometer type wattmeter improved?
Power Factor of an electrodynamometer can be improved by connecting a large resistor in series with the current coil.
How do you decide the pachage size of resistor with same value of resistance?
The package size roughly equates to wattage- the amount of power a resistor can safety dissipate without damage. Use your basic ohms law to figure out how much power will be dissipated by the resistor, and use the next largest size. A good safety factor is 2, so if you calculate the power is 1/4 watt, use a 1/2 watt resistor. One other factor is duty cycle. A component with a low duty cycle would need less of a safety factor, or perhaps could be sized according to the AVERAGE power in the resistor.
Why does the resistor current stay the same when you adjust the power factor?
A pure resistive load always has a power factor of one. This is because the current and voltage waveforms are in phase in an AC circuit.
What method improve power factor?
The most common method of improving the power factor of a load is to connected a capacitor or capacitor bank, of appropriate reactive power (expressed in reactive volt amperes), in parallel with the load.
What is the function of a cement resistor?
A cement resistor is typically used as a power resistor (a resistor whose power rating is greater than 1 W).
How do you find power generated in a resistor?
The power generated in a resistor is converted into heat. and that can be power which is converted into heat is the product of the voltage across the resistor and, current passing through the resistor. or the product of square of the current and the resistance offered by the resistor.
What are the basics of how flashlights work?
You need a conductor, power source and a resistor. You need a conductor, power source and a resistor. You need a conductor, power source and a resistor.
How must the voltage across a resistor change to reduce the current in the resistor by a factor of 3?
The voltage must reduce by the same factor - that is Ohm's law.
What is the relation between the size of the resistor and its value?
There is no relation between the resistor's ohms value and its size. The power of the resistor can be seen by its size. If the power is too small, the resistor can be destroyed.
2 resistors unequal value are in parallel. Would the power dissipated by the resistor with larger ohmic value be greater than the power dissipated by the resistor of lesser value?
No, because the power dissipated in a resistor is proportional to the square of the current through the resistor but only directly proportional to the resistance of the resistor (I^2 * R) and the current through the lower value resistor will be higher than the current through the higher value resistor, the lower value resistor will usually dissipate more power.
