assuming the point load acts in the centre, take the value under it as P*L / 4
where P=point load (kN)
L=length between supports
if its not in the middle, take it as P*a*b / 8
a=dist from left hand support to load
b=dist from right hand support to load
thanks,
Abdul wahab
The " in not in the middle formula" is incorrect.
Your Welcome
Paul
Parabolic, max moment at midspan of value wL^2/8 where w is the distributed load and L the length of the beam.
a slab of a house suupported with RCC frame column & beam, What will be the bending moment in different spans. ER. J.S.DEORI
It is a beam that is attached at aboundary that is free to rotate, like a hinge. It cannot develop a bending moment. It is often used to idealize a simply supported beam
The strength, S, of the beam is Mc/I where M = max moment to fail = PL/4 for load concentrated in the middle of the beam or WL/8 for uniformly distributed load. Here P is the concentrated load, W = distributed load, c = distance to outer fiber from neutral axis and I the area moment of inertia of the beam. L = length Solving for load maximum, P = 4IS/Lc for concentrated center load W = 8IS/Lc for distributed load
It actually depends on the type of beam it is. If it is a cantilever, the formula would be PL/2 and for a simply supported beam it would be PL/4
It depends on the loading conditions of the beam, it will generally occur close to the middle of the span.
zero
Parabolic, max moment at midspan of value wL^2/8 where w is the distributed load and L the length of the beam.
a slab of a house suupported with RCC frame column & beam, What will be the bending moment in different spans. ER. J.S.DEORI
It is a beam that is attached at aboundary that is free to rotate, like a hinge. It cannot develop a bending moment. It is often used to idealize a simply supported beam
The slabs that are supported only at end are called simply supported slabs i.e. there is no intermediate supports in the slab and there will be no support moment acting on the slab.
b'coz in smply supported beam it has two fixed ends
Yes, as long as your beam is relatively slender (i.e. L/d greater than about 2)
The strength, S, of the beam is Mc/I where M = max moment to fail = PL/4 for load concentrated in the middle of the beam or WL/8 for uniformly distributed load. Here P is the concentrated load, W = distributed load, c = distance to outer fiber from neutral axis and I the area moment of inertia of the beam. L = length Solving for load maximum, P = 4IS/Lc for concentrated center load W = 8IS/Lc for distributed load
It actually depends on the type of beam it is. If it is a cantilever, the formula would be PL/2 and for a simply supported beam it would be PL/4
Reinforcements is provided to resist moment and shear force, in a simply supported beam maximum moment at centre and its reduces towards (zero)support. so no 100% reinforcments at support required, so curtailment is possible (max 50%) at ends.
Sand Bending is a variation of Earth Bending, as sand is simply "little chunks of earth".