V_rms = V_peak / √2 so V_rms = 80/√2 = 56.6 V (3sf)
The RMS value of an AC voltage is VRMS = VPEAK / sqrt(2), where VPEAK = the voltage peak to neutral.AnswerThe average value of a sinusoidal a.c. voltage is zero.
It is the highest value of the amplitude, called the peak value. Scroll down to related links and look at "RMS voltage, peak voltage and peak-to-peak voltage". Look at the figure in the middle below the headline "RMS voltage, peak voltage and peak-to-peak voltage".
The average voltage is the rms voltage.Volts peak = volts RMS times 1.414Volts RMS = volts peak times 0.7071Use the link below to an RMS voltage, peak voltage and peak-to-peak voltage calculator.********************************The average voltage is not the r.m.s. voltage.The average voltage of a sine wave is 0.636 x the peak value. Conversely, peak voltage is 1.57 the mean or average.
The input voltage, an AC Sine Wave will have a Peak-to-Peak value equal to 2X its Peak value. Once rectified, all the Peaks will be either above or below the Zero reference line. They'll look like a series of identical bumps. The net value of the unrectified voltage will be Zero. The positive and negative waveforms canceling each other out. The rectified waveform will be all positive or negative and its net value will be non-zero. Its AVERAGE value will be .636 times its Peak value. Its Root Mean Square (RMS) value will be .707 times its Peak value. Its Peak-to-Peak value will equal 1X the Peak value.
You have to convert the peak voltage to an r.m.s. value, before inserting that value into the power equation.
RMS is used to determine the average power in an alternating current. Since the voltage in an A/C system oscillates between + and -, the actual average is zero. The RMS or "nominal" voltage is defined as the square root of the average value of the square of the current, and is about 70.7% of the peak value.************************************************************The r.m.s. value of an alternating current or voltage is the value of direct current or voltage which produces the same heating effect.Fo a sine wave, the r.m.s. value is 0.707 x the peak value.The average value is different; for a sine wave it is 0.636 x the peak value.
The RMS value of an AC voltage is VRMS = VPEAK / sqrt(2), where VPEAK = the voltage peak to neutral.AnswerThe average value of a sinusoidal a.c. voltage is zero.
Another name for average voltage is the RMS (Root Mean Square). This is a voltage derived from the peak to peak voltage multiplied by .707. If the peak to peak voltage is 170 volts then the average voltage (RMS) would be 170 x .707 = 120 volts.
ANSWER: The peak to peak voltage can be found by multiplying 120 v AC x 2.82= 339.41
Conversions of RMS voltage, peak voltage and peak-to-peak voltage. That are the used voltages. The expression "average" voltage is used for RMS voltage.Scroll down to related links and seach for "RMS voltage, peak voltage and peak-to-peak voltage".Answer'Average' is not the same as 'root mean square'. As the average value of a sinusoidal voltage is zero, you cannot convert it to a peak-to-peak value.
It is the highest value of the amplitude, called the peak value. Scroll down to related links and look at "RMS voltage, peak voltage and peak-to-peak voltage". Look at the figure in the middle below the headline "RMS voltage, peak voltage and peak-to-peak voltage".
Peak voltage of an AC voltage is the value at its highest or lowest point.RMS (Root Mean Square) voltage of an AC voltage is a mathematical derivation involving the square root of the average value of the squares of samples of the voltage as the sample interval approaches zero.Average voltage is simply that - the average or mean voltage.For a true sine wave, RMS and average are equivalent, but they are not equivalent when the wave is distorted, or has some other shape such as triangular.RMS is the best way to measure an AC voltage, as it gives you a true reading of the amount of power that the voltage can deliver.One issue with non-RMS AC meters is that they typically measure the rectified, filtered peak value and then compensate by dividing by 1.4. This is not correct unless the voltage is a sine wave.AnswerThe peak value of an a.c. voltage or current is the amplitude of that voltage or current waveform -i.e. the maximum value of voltage or current in either the positive or the negative sense.The root-mean-square (rms) value of an a.c. voltage or current. For a sinusoidal waveform, the rms value is 0.707 times the peak value (amplitude). A.C. voltages or currents are always quoted in rms values unless otherwise specified.The average value of an a.c. voltage or current is zero over one complete cycle so, when used, it applies only over one half cycle. Therefore, the average value for one-half cycle of a sine wave is 0.637 times the peak value. Average values are of little relevance to a.c. calculations.
Assuming "quoted value" to be RMS value, or average, [what you would see on a meter], the peak would be that value times 1.414. Going backward, peak times .707 is RMS.
The average voltage is the rms voltage.Volts peak = volts RMS times 1.414Volts RMS = volts peak times 0.7071Use the link below to an RMS voltage, peak voltage and peak-to-peak voltage calculator.********************************The average voltage is not the r.m.s. voltage.The average voltage of a sine wave is 0.636 x the peak value. Conversely, peak voltage is 1.57 the mean or average.
The input voltage, an AC Sine Wave will have a Peak-to-Peak value equal to 2X its Peak value. Once rectified, all the Peaks will be either above or below the Zero reference line. They'll look like a series of identical bumps. The net value of the unrectified voltage will be Zero. The positive and negative waveforms canceling each other out. The rectified waveform will be all positive or negative and its net value will be non-zero. Its AVERAGE value will be .636 times its Peak value. Its Root Mean Square (RMS) value will be .707 times its Peak value. Its Peak-to-Peak value will equal 1X the Peak value.
You have to convert the peak voltage to an r.m.s. value, before inserting that value into the power equation.
The RMS value of a sinusoidal voltage is 2/pi x (the peak voltage).The time average of a sinusoidal voltage is 1/sqrt(2) x (the peak voltage).So I guess the difference is ( 2/pi minus 1/sqrt(2) ) x (peak voltage) = 0.07 of the peak voltage. (rounded)The significance is:The RMS value used to be called the "heating value". It's the value of the DC thatyou'd have to pass through a toaster coil to produce the same heat as this AC.But the heating effect at every instant is not proportional to the voltage. It's proportionalto (the voltage)2. So the heating effect is stronger near the top of the waveform thanyou'd expect, and it's stronger than a DC at the average value.