The symbol, kV.A (not 'kva'), represents kilovolt amperes, which is the unit of measurement for apparent power -i.e. the product of supply voltage and load current in an a.c. circuit. The symbol, kV (not'kv'), represents kilovolts, which is the unit of measurement for potential difference.
To calculate the power required for a radiographic exposure at 76 kV and 500 mA, you can use the formula: Power (P) = Voltage (V) × Current (I). Here, P = 76 kV × 500 mA = 76,000 volts × 0.5 amps = 38,000 watts, or 38 kW. Therefore, the power required for the radiographic exposure is 38 kW.
The higher-voltage line will have longer insulators and the line conductors will be further apart. And the symbol for kilovolt is 'kV', not 'kv'.
KV, kilovolts, or kilojoules per coulomb is not the same thing as KVA, kilovoltamperes, or kilojoules per second, and no direct comparison exists. Please restate the question.
1kva means 1kv per ampere therefore 1 amp flowing and 1 kv deduce to be the product of the two or 1kw
Find out how much current the motor draws, then look up wire tables to find out the size of wire. Ask an electrician if you are not unfamiliar with this because working at 6.6 kV is definitely lethal for the unqualified.
Multiply by Amps.
Considering it is kw for kilowatt and not kv. 1 megawatt = 1000 kilowatt.
KV is kiloVolt and KWH is KiloWatt Hour
basically there will not be any difference between them. the capacity of equipment will be more such as the CB rating will be more basically there will not be any difference between them. the capacity of equipment will be more such as the CB rating will be more
The lower-case 'k' in 'kV' (not 'kv') is a multiplier, representing 'kilo', meaning 'a thousand times', and the upper-case 'V' represents 'volts', the SI unit for potential difference. So a '220-kV' cable has a line voltage (voltage between conductors) of 220 kV.
With a dc system the kW are always equal to the kV times the amps. It's only with ac that the kW are usually less than the kVA by a factor called the power factor.
kV is kilovolts, kW is kilowatts, kVA is kilovolt amps and kVAR is kilovolt-amps reactive. A common formula is kVA-squared = kW-squared + kVAR-squared.
kV measures the voltage, while the kW measures the power. Apart from a general relationship that high power is usually associated with high voltage, nothing more definite can be said.
To calculate the power required for a radiographic exposure at 76 kV and 500 mA, you can use the formula: Power (P) = Voltage (V) × Current (I). Here, P = 76 kV × 500 mA = 76,000 volts × 0.5 amps = 38,000 watts, or 38 kW. Therefore, the power required for the radiographic exposure is 38 kW.
"kV" is referring to voltage, "KW" is referring to power. This is synonomous with asking "how many apples are in the tree?" without giving any more information about the tree, or back to your question, the current.
The higher-voltage line will have longer insulators and the line conductors will be further apart. And the symbol for kilovolt is 'kV', not 'kv'.
KV, kilovolts, or kilojoules per coulomb is not the same thing as KVA, kilovoltamperes, or kilojoules per second, and no direct comparison exists. Please restate the question.