i) leakage flux is those flux which goes through the air and linkage flux is those flux whose go through the cell. ii)leakage flux is the loss at flux but linkage flu is warning flux. iii)leakage flux is cause of eddy current loss and linkage flux is case of copper loss.
As per transformer equation,E=4.44 * freq * flux * Turns.So E/ freq =Flux. So when a transformer is designed for 60Hz ,it CANNOT be operated at 50Hz and if operated may create heating effects and core saturation etc. Because E/60< E/50. However the converse condition is true i.e. a 50 HZ transformer can be used for 60Hz application Because E/50>E/60
light speeeed mofos
Basically useful fluke is the flux that flows with in the magnetic circuit of an armature. That is why when there is an air gap the flux enters the armature which makes it useful flux! Hope that answers your question!
EMF equation of DC GeneratorE = (ΦNPZ) / (60 * A)where,E = e.m.f induced in any parallel path in armatureΦ = flux per pole in weberN = armature rotation in revolutions per minute (r.p.m)P = No.of generator polesZ = total number of armature conductorsA = No.of parallel paths in armature
E E. O'Brien has written: 'On the flux of heat through laminar wavy liquid layers' 'On the flux of heat through laminar thin films'
Photon flux can be calculated using the formula: photon flux = v * E, where v is the frequency of the photons and E is the energy of each photon. By multiplying the frequency of the photons by the energy of each photon, you can determine the photon flux.
the flux goes about 95 km with a lipo battery.
Scalar
The SI unit of electric flux is the volt-meter (Vm). It is calculated by multiplying the electric field strength (E) by the area (A) perpendicular to the field. The formula is E A.
acc. to gauses law..flux is equal to total charge/e or Q/e as there are six sides of the cube so flux through one surface will be Q/6e
To determine the electric flux through a surface, you can use Gauss's Law. This law states that the electric flux through a closed surface is equal to the charge enclosed by the surface divided by the permittivity of free space. The formula for electric flux is E A cos(), where E is the electric field, A is the area of the surface, and is the angle between the electric field and the normal to the surface.
As we know that electric flux is the total number of electric lines of forces passing through a surface. Maximum Flux: Electric flux through a surface will be maximum when electric lines of forces are perpendicular to the surface. Minimum flux: Electric flux through a surface will be minimum or zero when electric lines of forces are parallel to the surface.
The electric flux through the curved surface of the hemisphere can be calculated using the formula Φ = E * A, where E is the electric field strength and A is the area of the curved surface. The area of the curved surface of a hemisphere can be calculated as 2πR^2, where R is the radius of the hemisphere. So, the electric flux through the curved surface of the hemisphere is Φ = E * 2πR^2.
i) leakage flux is those flux which goes through the air and linkage flux is those flux whose go through the cell. ii)leakage flux is the loss at flux but linkage flu is warning flux. iii)leakage flux is cause of eddy current loss and linkage flux is case of copper loss.
The HPI E-Firestorm does about 20 mph. The HPI E-Firestorm Flux does 44 mph. The Nitro firestorm rtr does 48mph
Using the Gauss' Law of Magnetism We know total flux will be zero flux(top)+flux(bottom)+flux(curved side)=0 ------- (a) flux(bottom)= -25e-3 (GIVEN) (-ve shows inward direction) flux(top)=B*A=(1.6e-3)*[3.14*(0.12)^2]=2.304e-5 Put the values in eq (a) you'll get flux(curved side)= +24.97e-3 (+ve shows direction is outward)