For the amperage of a metal halide fixture look for the nameplate which can be found on the side of the ballast. There it will tell you what the amperage of the fixture draws. Knowing what one fixture draws will allow you to size the lighting circuit for wire and breaker sizes.
The formula is: current (in amps) = power (in watts) , divided by (240 times the power factor). The power factor is 1 for incandescent light or heaters, otherwise it can be assumed to be 0.75 for other loads.
The current will of course vary with the intensity of the imparted light and with the temperature of the panel.
Voltage x Current = Power So Power / voltage = current Now you do the math
The formula you are looking for is I = W/E. Amps = Watts/Volts.
No. Although there is a voltage drop across the filament of an incandescent light bulb, the amount of current flowing out is identical to what flows in: current in = current out. That is an important fact to always keep in mind when solving simple electrical circuits: the sum of the currents flowing into a node equals the sum of the currents flowing out of it.
The microwave formula for calculating the wavelength of a given frequency is: Wavelength () Speed of Light (c) / Frequency (f).
The question isn't what you're powering with a particular gauge of wire, but what's the current draw. If the metal halide light can run on a 15 Amp breaker (from the breaker panel), fine use your metal halide in your residential application and run it on the 14 gauge wire.
The formula for calculating electromagnetic wave intensity is given by the equation: Intensity (Electric field strength)2 / (2 Permittivity of free space Speed of light)
The formula for calculating the intensity of an electromagnetic wave is given by I E2 / (2 c), where I is the intensity, E is the electric field strength, is the permeability of the medium, and c is the speed of light.
Assuming an incandescent bulb and a 120 volt supply the formula is Watts = Volts x Amps x Power Factor where PF = 1 for resistive load. Amps = 400 / 120.
The formula for calculating the amplitude of an electric field is given by E cB, where E represents the electric field amplitude, c is the speed of light in a vacuum, and B is the magnetic field amplitude.
Metal halide lights are a type of high-intensity discharge light. They're frequently used as grow lights for plants in conjunction with HPS (high pressure sodium) lights. MH lights are better for the earlier vegetative growth stages.
The light intensity formula is I P/A, where I is the intensity of light, P is the power of the light source, and A is the area over which the light is spread. This formula can be used to measure the brightness of a light source by calculating the intensity of the light emitted per unit area. The higher the intensity value, the brighter the light source is perceived to be.
The "salt" you are referring to is actually called silver-halide and are more commonly known as "silver salts". When silver-halide crystals are exposed to light, they form a compound known as "metallic silver"
The formula for calculating the index of refraction is n = c/v, where n is the index of refraction, c is the speed of light in a vacuum, and v is the speed of light in the medium.
Metal-halide light is helpful for plant growth and is often used for indoor plant growing applications. Metal-halide lights produce blue-frequency light. They can provide the temperature , as well as the spectrum of light that encourages plant growth.
Metal halide lights can flicker due to a variety of reasons, such as a failing ballast, loose electrical connections, or improper voltage supply. These issues can lead to fluctuations in the electrical current, causing the light to flicker. Regular maintenance and proper installation can help prevent flickering in metal halide lights.