If the area you're referring to is the cross-sectional area of the conductor: you can think of the cross-sectional area of a wire as the thickness of that wire. If you bundled two wires together in parallel, that would be a bit like having one, thicker wire, wouldn't it?
So increasing the area is analogous to adding more pathways for current to travel in parallel. Metals carry current on their surface, but also through electron "bands" in their interior -- increasing area means adding more bands = adding more pathways. And adding more pathways reduces resistance.
Cell constant(C) = Resistance(R) X Specific Conductivity(K)
Resistance is directly proportional to the resistivity and length of the conductor, and inversely-proportional to its cross-sectional area. As resistivity is affected by temperature, we can say that temperature indirectly affects resistance.
L1-L0=(RESISTANCE*AREA)/RESISTIVITY where L1=INIIAL LENGTH and L2=FINAL LENGTH
The relation between bending moment and the second moment of area of the cross-section and the stress at a distance y from the neutral axis is stress=bending moment * y / moment of inertia of the beam cross-section
I think the equation you are looking for is Resistance (ohms) = Resistivity * Length / Area or R=p*L/A. This is the resistance of a circular wire with cross-section of A, length of L, and material with resistivity p. So to get area: Area = Resistivity * Length / Resistance.
Force = Pressure x Area
The relationship between resistance and cross-sectional area in a conductor is inversely proportional. This means that as the cross-sectional area of a conductor increases, the resistance decreases, and vice versa. This relationship is described by the formula: Resistance (resistivity x length) / cross-sectional area.
It can't be done. You must also know at least any one of the following: Perimeter Relation between length and breath Relation between Area and length Relation between Area and breath Relation between perimeter and Area Breath and so on...........
We can reduce the supply voltage from the ohms law relation.......v=ir... resistance is directly proportional to supply voltage...or.....we can control the resistance by the relation by R is directly proportional to l/a l=length a=area
by ASR do you mean Area Specific Resistance?
The current flowing through a conductor is directly proportional to the cross-sectional area of the conductor. This means that as the area of the conductor increases, the current flowing through it also increases, assuming the resistance and voltage remain constant.
Pressure = force / area
In relation to the area of a circle: pi*radius^2
There is no direct relation between the area of a sector and the length of an arc. You must know the radius (or diameter) or the angle of the sector at the centre.
The formula to find resistance force is given by R = F/A, where R is the resistance force, F is the force applied, and A is the area over which the force is applied. This formula is often used in physics and engineering to determine the resistance force in various scenarios.
R is the electrical resistance,A is the cross-sectional area,l is the length of the piece of material.
Resistance (Ohms) = Voltage (v) / Current (I)