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How does the coil of wire wrap around the iron core works as a surge suppressor?
A coil of wire wrapped around an iron core forms an inductor. In AC systems, an inductor's impedance appears equivalent to j*w*L (j = i = imaginary number, w = omega = frequency in radians, L = inductance). A surge is inherently high frequency. Here's an example to help explain why this acts as a surge supressor: Say I have a 10mH surge supressing inductor. My device uses 1 amp of current at 120 volts, so its' resistance is 120 ohms. Under normal operation (60 Hz), the inductor's impedance appears as (j*2*pi*60*10/1,000) 3.8 ohms. Voltage to my device is ~120 volts, and voltage dropped (or "supressed") is (3.8 / (120 + 3.8) * 120 ) = 3.7 volts. My device is only seeing 116.3 volts with this inductor in place, but that's not enough of a dip to hurt its' operation. A power surge hits this device. This power surge is at a frequency of 50kHz, and a voltage of 80v (an overvoltage to my device of 120 + 80 = 200 volts). The impedance of the inductor "looks like" (j*pi*50,000*10/1,000) 3141 ohms, which is in series with my 120 ohm load. The surge voltage dropped across the inductor is (3141 / (3141+120) * 80) = 77 volts, so my device gets hit with ~3 surge volts (total voltage = 60 Hz voltage of 116.3 + 50kHz voltage of 3 = 119.3 volts).
Why the current increases upto resenance frequency and decreases there after in a series LCR circuit?
At resonance, the L and C impedance cancels out, so the current can be calculated based on the resistance and applied voltage. Imagine increasing frequency of the supply from 0 Hz to very high. At low frequency, the impedance of the inductor is ~0 (defined as Zl = w*L*j), and the impedance of the capacitor is very large (defined as Zc = 1 / (w*C*j)). As you increase the frequency, the impedance of the capacitor will decrease, as the impedance of the inductor increases. At some point (the resonant frequency), these two will be equal, with opposite signs. After crossing the resonant frequency, the inductor impedance will continue growing larger than the capacitor impedance until the total impedance approaches infinite.
What is the reactance of a 3-H inductor when the frequency is 100Hz?
The reactance (X_L) of an inductor is calculated using the formula (X_L = 2\pi f L), where (f) is the frequency in hertz and (L) is the inductance in henries. For a 3-H inductor at a frequency of 100 Hz, the reactance is (X_L = 2\pi (100)(3) \approx 1884.96 , \Omega). Thus, the reactance of the 3-H inductor at 100 Hz is approximately 1885 ohms.
How can you calculate current drawn in 60 HZ circuit?
You need to divide the supply voltage by the impedance of the load. The impedance of the load is the vectorial sum of its resistance and reactance, where reactance is proportional to frequency.
What is x r ratio?
x/r ratio is reactance/resistance where reactance is impedance * frequency (60 hz)
How does the coil of wire wrap around the iron core works as a surge suppressor?
A coil of wire wrapped around an iron core forms an inductor. In AC systems, an inductor's impedance appears equivalent to j*w*L (j = i = imaginary number, w = omega = frequency in radians, L = inductance). A surge is inherently high frequency. Here's an example to help explain why this acts as a surge supressor: Say I have a 10mH surge supressing inductor. My device uses 1 amp of current at 120 volts, so its' resistance is 120 ohms. Under normal operation (60 Hz), the inductor's impedance appears as (j*2*pi*60*10/1,000) 3.8 ohms. Voltage to my device is ~120 volts, and voltage dropped (or "supressed") is (3.8 / (120 + 3.8) * 120 ) = 3.7 volts. My device is only seeing 116.3 volts with this inductor in place, but that's not enough of a dip to hurt its' operation. A power surge hits this device. This power surge is at a frequency of 50kHz, and a voltage of 80v (an overvoltage to my device of 120 + 80 = 200 volts). The impedance of the inductor "looks like" (j*pi*50,000*10/1,000) 3141 ohms, which is in series with my 120 ohm load. The surge voltage dropped across the inductor is (3141 / (3141+120) * 80) = 77 volts, so my device gets hit with ~3 surge volts (total voltage = 60 Hz voltage of 116.3 + 50kHz voltage of 3 = 119.3 volts).
What is the inductive reactance of a 2 H inductor in a 60 Hz AC circuit?
The inductive reactance of a 15 Henry inductor at 60 Hz is about 5.7 KOhms. (2 pi f l)
Why the current increases upto resenance frequency and decreases there after in a series LCR circuit?
At resonance, the L and C impedance cancels out, so the current can be calculated based on the resistance and applied voltage. Imagine increasing frequency of the supply from 0 Hz to very high. At low frequency, the impedance of the inductor is ~0 (defined as Zl = w*L*j), and the impedance of the capacitor is very large (defined as Zc = 1 / (w*C*j)). As you increase the frequency, the impedance of the capacitor will decrease, as the impedance of the inductor increases. At some point (the resonant frequency), these two will be equal, with opposite signs. After crossing the resonant frequency, the inductor impedance will continue growing larger than the capacitor impedance until the total impedance approaches infinite.
If a loudspeaker has a frequency of 120 Hz how often does it vibrate?
120 Hz means a vibration 120 cycles per second.
What is the reactance of a 3-H inductor when the frequency is 100Hz?
The reactance (X_L) of an inductor is calculated using the formula (X_L = 2\pi f L), where (f) is the frequency in hertz and (L) is the inductance in henries. For a 3-H inductor at a frequency of 100 Hz, the reactance is (X_L = 2\pi (100)(3) \approx 1884.96 , \Omega). Thus, the reactance of the 3-H inductor at 100 Hz is approximately 1885 ohms.
What is the frequency of ripple component in the output inductor filter?
It depends on the rectifier. For a half-wave, it's the same as the AC mains: i.e. 60 Hz mains gives 60 Hz ripple. For a full-wave or a bridge, it's twice the AC mains: 60 Hz mains gives 120 Hz ripple. Three-phase systems are more complicated, so you would need to check in an electrical engineering book.
What is the frequency of ripple component in the output of inductor filter?
It depends on the rectifier. For a half-wave, it's the same as the AC mains: i.e. 60 Hz mains gives 60 Hz ripple. For a full-wave or a bridge, it's twice the AC mains: 60 Hz mains gives 120 Hz ripple. Three-phase systems are more complicated, so you would need to check in an electrical engineering book.
What would be the inductive reactance ohmsof a 9 Henry inductor at a frequency of 60 Hz?
Inductive reactence is given by Xl = 2*pi*F*L = 2*3.14*60*9 = 3.912 K Ohm
How does an electric clock made to operate on 60 HZ 120 V system behave if pluged into a 50 HZ 120 V system?
As clock motors are synchronous in design for a particular frequency, the 60 Hz clock will run slower on 50 Hz.
Voltage in Canada?
120 V @ 60 Hz
How can you calculate current drawn in 60 HZ circuit?
You need to divide the supply voltage by the impedance of the load. The impedance of the load is the vectorial sum of its resistance and reactance, where reactance is proportional to frequency.
What is x r ratio?
x/r ratio is reactance/resistance where reactance is impedance * frequency (60 hz)
