if it is a signed int the the range is -32768 to 32767
if its unsigned then 0 to 65535
int max(int arr[], int arrSize){int maximum = arr[0];for (int i = 0; i < arrSize; i++){if (maximum < arr[i]){maximum = arr;}}return maximum;}
no
In JavaA char in Java is a 16-bit integer, which maps to a subset of Unicode.In C A char in C is an 8-bit integer, which maps to standard ASCII.Note that in both Java and in C you can use a char value like a normal integer type: char c = 48;
To define any integer type value.
Yes, an integer can be assigned as a float value.But it get stored as a float value, that is an implicit type conversion occurs during compilation.Smaller data types are convertible to larger data types.eg:float b=12;// an integer constant is assigned to a float variableprintf("%f",b);// when printing b it will print as 12.000000
see the program
int max(int arr[], int arrSize){int maximum = arr[0];for (int i = 0; i < arrSize; i++){if (maximum < arr[i]){maximum = arr;}}return maximum;}
no
If ( c - 8 ) is an odd integer, then ( c ) must be an odd integer as well. This is because subtracting an even number (8) from an odd number results in an odd number. Therefore, possible values for ( c ) could be any odd integer such as 1, 3, 5, 7, etc. In general, ( c ) can be expressed as ( c = 2k + 1 ), where ( k ) is an integer.
The maximum charge that can be stored on a capacitor is determined by the capacitance of the capacitor and the voltage applied to it. The formula to calculate the maximum charge is Q CV, where Q is the charge, C is the capacitance, and V is the voltage.
In JavaA char in Java is a 16-bit integer, which maps to a subset of Unicode.In C A char in C is an 8-bit integer, which maps to standard ASCII.Note that in both Java and in C you can use a char value like a normal integer type: char c = 48;
The formula for maximum energy stored in a capacitor is given by ( E = \frac{1}{2}CV^2 ), where ( E ) is the energy stored, ( C ) is the capacitance of the capacitor, and ( V ) is the voltage across the capacitor.
To define any integer type value.
Yes, an integer can be assigned as a float value.But it get stored as a float value, that is an implicit type conversion occurs during compilation.Smaller data types are convertible to larger data types.eg:float b=12;// an integer constant is assigned to a float variableprintf("%f",b);// when printing b it will print as 12.000000
When there is no addressable value in program, then compiler will give lvalue error. Lvalue or location value is an address that is stored into while rvalue is the "read" value, ie., value of a constant or the value stored at a location. In the assignment a = 31; we have the lvalue of a used on the left hand side and the integer contant value 31 assigned to this location. In the assignment b = a; we have the rvalue of a (31) used to assign to the lvalue of b . So depending on which side of an assignment, we use the variable a , we get two different behaviors
In a managed heap, a boxed value type is stored as an object. When a value type (like an integer or a struct) is boxed, it is wrapped in an object and allocated memory on the heap, allowing it to be treated like a reference type. The original value type remains on the stack or in its original location, while the boxed version on the heap holds a reference to this value. This allows for polymorphism and other object-oriented features in languages like C#.
That is correct - In c plus plus you cannot assign integer value to enum - You can only assign an enum value to an enum. Even though an enum looks like an integer, it is not. It is an enum, and C++ implements strict type checking to reduce the probability of bad programming practices. enum ColorCode {black, brown, red, orange, yellow, green, blue, violet, grey, white}; ColorCode myColorCode; myColorCode = yellow; Even though yellow has an integer value of 4, you cannot say myColorCode = 4.