Active power: Power that is actually consumed. If you, in the time domain, multiply voltage and current continuously (i.e. via oscilloscope), then take the time-average of the result, that is related to active power.
Reactive power: Power that is stored in components, then released again back to the source through the AC cycle. Capacitors and inductors both do this, just in opposite phase.
Apparent power: The peak voltage times the peak current (or the RMS voltage times the RMS current, depending on if you're looking at peak power or average power). A power supply must be capable of outputting the full apparent power delivered to a circuit, not just the active power.
Apparent Power=Active Power+Reactive Power or Active Power=VI Cos(Phase Angle) Reactive Power=VI Sin(Phase Angle) Apparent Power= VI
Use a wattmeter, as it only reads 'real power' of your load. Use an ammeter and a voltmeter, and the product of the two readings will give you 'apparent power' of your load. Since apparent power is the vector sum of real power and reactive power, use the following equation to find the reactive power of your load: (reactive power)2 = (apparent power)2 - (real power)2
If a load takes 50 kW at a power factor of 0.5 lagging calculate the apparent power and reactive power Answer: Apparent power = Active power / Power Factor In this case, Active power = 50 kW and power factor = 0.5 So Apparent power = 50/0.5 = 100 KVA
You may be fishing for the answer "AC" or "alternating current", sinceno reactive component of power is developed in response to DC.AnswerSince true power (in watts) is associated with resistive components, and reactive power (in reactive volt amperes) is associated with reactive loads, the vector-sum of these is called apparent power (in volt amperes). So the answer you are looking for is apparent power.
On an electric bill, kVA stands for "kilovolt-ampere", which is a unit of apparent power. It measures the total electrical power, both real and reactive, that is consumed by a device or a facility. It represents the maximum power that the electrical system can support and is used by utilities to determine the capacity requirements for supplying electricity to a customer. The actual power consumption in kilowatts (kW) is often lower than the apparent power in kVA due to the presence of reactive elements, such as inductive loads, which cause the power factor to be less than 1.
Apparent Power=Active Power+Reactive Power or Active Power=VI Cos(Phase Angle) Reactive Power=VI Sin(Phase Angle) Apparent Power= VI
A voltamp is a unit of apparent power, which is the combination of voltage and current in an electrical circuit. A watt, on the other hand, is a unit of real power, which is the actual power consumed by a device. The relationship between voltamps and watts is that in an ideal circuit with no reactive components, the apparent power (voltamps) is equal to the real power (watts). However, in real-world circuits with reactive components like inductors and capacitors, the apparent power can be greater than the real power due to the presence of reactive power.
Use a wattmeter, as it only reads 'real power' of your load. Use an ammeter and a voltmeter, and the product of the two readings will give you 'apparent power' of your load. Since apparent power is the vector sum of real power and reactive power, use the following equation to find the reactive power of your load: (reactive power)2 = (apparent power)2 - (real power)2
70 kVA stands for 70 kilovolt-amperes, which is a unit used to measure electrical power. It represents the apparent power in an electrical system, combining both the active (real) power and the reactive power.
A VAr meter only measures the reactive (imaginary) power. Apparent power is a combination of real and reactive power; thus having a VAr meter will not suffice to measure apparent power. Likewise, because the VAr meter only measures reactive power, it does not provide any information on real power.
According to Wikipedia, all forms of power can be expressed in Watts, but typically one expresses only REAL Power in Watts (& Kilowatts).The standard is to express Apparent Power in Volt-Amperes (VA) (& KVA).The kilowatt is the unit of measure for true power; apparent power is measured in volt amperes.However, the volt ampere and the reactive volt ampere (for reactive power) are traditional units, used to help differentiate between apparent, true, and reactive power. SI recognises the watt as the unit for each.
Apparent power is the vectorial sum of the true power and reactive power. In this case, the total reactive power is the difference between 7200 var and 3600 var -i.e. 3600 var.So you can now use the equation,(apparent power)2 = (true power)2 + (total reactive power)2,to determine your answer.
If a load takes 50 kW at a power factor of 0.5 lagging calculate the apparent power and reactive power Answer: Apparent power = Active power / Power Factor In this case, Active power = 50 kW and power factor = 0.5 So Apparent power = 50/0.5 = 100 KVA
All three refer to a form of power. Active power units use watts, apparent power uses voltamps, and reactive power uses voltampreactives. So, they are Wh, VAh, and VARh. The M is the prefix for Mega, meaning 10^6.
Reactive power is the portion of apparent power that does not do any useful work, but instead oscillates between the source and load causing voltage and current to be out of phase.
Apparent power must be used for this is the total amount of power you need to generate. Apparent power includes all the loses of energy while real power is the power used by the electrical appliances. If you are talking about environmental impact then apparent power is the one you need because this is the overall power needed.
You may be fishing for the answer "AC" or "alternating current", sinceno reactive component of power is developed in response to DC.AnswerSince true power (in watts) is associated with resistive components, and reactive power (in reactive volt amperes) is associated with reactive loads, the vector-sum of these is called apparent power (in volt amperes). So the answer you are looking for is apparent power.