The junction (diode or transistor) will be destroyed.
A: Actually it is only one transistor required for amplification the other junction can be a diode. As current Begin to flow it causes a bias across one junction which is opposite biasing for the other, A good differential amplifier will have those junction virtually at the same point with a very good current source because any mismatched will cause and output without any input. It is called voltage offset on the other end if the feedback current is very small it will also produce an output voltage offset known as current offset or basically errors
No freaking way but it would make an excellent low level switch if forced at beta of 10
Voltage is applied between the collector and emitter. A signal is applied between the base and emitter. The input signal will control how much the transistor turns on and the larger current flowing across the Collector/Emitter will be the same, but larger, than the input. Therefore amplified.To keep the transistor switched on and to prevent the input signal switching it off, the transistor has to be biased on. This is usually done with a network of resistors on the base, raising the voltage to keep it conducting.
If the EBJ is forward baise and the CBJ is reverse baised then the transistor will in the active/forward mode of operation.
a transistor in active region when emitter junction is forward biased nd collector junction is reverse biased
To know if a transistor is PNP or an NPN,the following should be verified:For a PNP transistor, the base-collector junction is forward biased while the base-emitter junction is reversed biased.For an NPN transistor, the base-emitter junction is forward biased while the base -collector junction is reversed biased.
For a transistor to be in active region : Base Emitter junction should be forward biased and Emitter collector junction should be reverse biased.
Yes1
The junction (diode or transistor) will be destroyed.
Because the insulation between the gate and the channel is only a reverse biased PN junction. If this junction were to become forward biased the jfet would no longer operate as a transistor at those times.
The voltage across a forward-biased PN junction in a semiconductor diode or transistor.
Emitter-Base junction should be forward biased.Collector-Base junction should be reverse biased.
A: Actually it is only one transistor required for amplification the other junction can be a diode. As current Begin to flow it causes a bias across one junction which is opposite biasing for the other, A good differential amplifier will have those junction virtually at the same point with a very good current source because any mismatched will cause and output without any input. It is called voltage offset on the other end if the feedback current is very small it will also produce an output voltage offset known as current offset or basically errors
No freaking way but it would make an excellent low level switch if forced at beta of 10
Voltage is applied between the collector and emitter. A signal is applied between the base and emitter. The input signal will control how much the transistor turns on and the larger current flowing across the Collector/Emitter will be the same, but larger, than the input. Therefore amplified.To keep the transistor switched on and to prevent the input signal switching it off, the transistor has to be biased on. This is usually done with a network of resistors on the base, raising the voltage to keep it conducting.
If the EBJ is forward baise and the CBJ is reverse baised then the transistor will in the active/forward mode of operation.