The secondary current is determined by the load, not by the transformer. For example, if the secondary voltage is 50 V and the load is 100 ohms, then the secondary current will be 0.5 A. If the load is 25 ohms, then the secondary current will be 2 A. It is important that a continuous secondary current doesn't exceed the rated secondary current of the transformer.
I depends on the voltage.
The product of the secondary rated current and the secondary rated voltage will give you the rated V.A of the transformer.
Presumably, you are asking what is the rated secondary current for a 45 kV.A (not 'kva') transformer? The answer depends on its rated secondary voltage. To obtain the rated secondary current, you divide the (apparent) power rating by its secondary rated voltage.
It tells us how much is the transformer utilised in a given process. For a rectifier,TUF =(D.c.power delivered to the load)/(power rating of transformer secondary)
copper loss is directly propostional to I (AMPERE) and iron loss directly propostional to V (VOLTAGE) then total losses is equal to volt ampere hence the rating of transformer in KVA. SULTAN
I depends on the voltage.
The product of the secondary rated current and the secondary rated voltage will give you the rated V.A of the transformer.
This is the rated output of the transformer, obtained by multiplying the rated secondary voltage by the rated secondary current. And it's 'kV.A', not 'kva'.
Transformer utilization factor is the ration of power delivered to the load and ac rating of the transformer secondary.
The amp rating for a 100VA transformer will vary depending on the actual voltage of the transformer. Transformers have both a primary and a secondary voltage.
because we dont know power factor of the secondary laod
Presumably, you are asking what is the rated secondary current for a 45 kV.A (not 'kva') transformer? The answer depends on its rated secondary voltage. To obtain the rated secondary current, you divide the (apparent) power rating by its secondary rated voltage.
It tells us how much is the transformer utilised in a given process. For a rectifier,TUF =(D.c.power delivered to the load)/(power rating of transformer secondary)
copper loss is directly propostional to I (AMPERE) and iron loss directly propostional to V (VOLTAGE) then total losses is equal to volt ampere hence the rating of transformer in KVA. SULTAN
The VA of the transformer is the product of the amps x the volts. V x A = Watts. 50kVa is equal to 50,000 watts. It holds true on the primary and the secondary. The formula to use is I = W/E. Amperage = Watts (V x A)/volts.AnswerThe above answer will determine the rated currents of the primary/secondary windings. But the actual currents (which shouldn't exceed their rated values for any length of time) are determined by the load. For example, with no load, no secondary current will be flowing, and the primary current will be reduced to its magnetising current value.
The secondary current of a transformer is determined by the load and the secondary voltage applied to that load, and this, in turn, will determine the primary current by the inverse of the turns ratio. However, if you are asking about a transformer's rated secondary and primary currents, then you need to divide the transformer's apparent power rating (expressed in volt amperes) by the rated secondary and primary voltages respectively.
Power transformers have an impedance (Z) rating that is listed in %. So the nameplate might state 5% Z for example. What this means is that when the secondary conductors are bolted together then 5% of the rated primary voltage is applied and will generate 100% current in flow in the secondary. Example: you have a 75KVA Delta-Wye 5% Z transformer with a 480V primary rating and 208/12 secondary rating. The amp rating of the secondary is 208A [75,000/(1.732x208)] So if you applied 24VAC to the primary with the secondary bolted together with busbar then you would have 208A of current flow.