What is the total capacitance of capacitors connected in series C11989F C2994F?

Answer 1

To find the total capacitance ( C ) of capacitors connected in series, you can use the formula ( \frac{1}{C} = \frac{1}{C_1} + \frac{1}{C_2} ). For capacitors ( C_1 = 11989 , \text{F} ) and ( C_2 = 2994 , \text{F} ), this gives:

[ \frac{1}{C} = \frac{1}{11989} + \frac{1}{2994} \approx 0.0000834 + 0.000334 = 0.0004174 ]

Calculating ( C ) yields approximately ( 2391.5 , \text{F} ). Thus, the total capacitance is about ( 2391.5 , \text{F} ).