A voltage or current source in series with a circuit breaker or fuse in series with a switch in series with a light bulb.
The first thing you need to know is the internal resistance of the current source, the voltage source will have the same internal resistance. Then compute the open circuit voltage of the current source, this will be the voltage of the voltage source. You are now done.
Compute the open load voltage of the current source across its shunt resistance.This voltage becomes the voltage source's voltage.Move the current source's shunt resistance to the voltage source's series resistance.Insert the new voltage source into the original circuit in place of the current source.
The question is vague.A current source is the short form of constant current source.A voltage source, on the other hand, is the short form of constant voltage source.That being so, then no, a current source is not available in any circuit.
The reason for the total voltage drops across the capacitance and inductance IN AN AC CIRCUIT has to do with the different phase angles of the voltages.First, current is the same value and same phase angle everywhere in a series circuit. But, voltage across a capacitor lags current by 90 degrees (capacitor current leads voltage). Next, voltage across a pure inductance leads current by 90 degrees (inductor current lags voltage).The rule that all voltages in a series circuit have to add to the supply voltage still applies, but in this case, the voltage drops are added VECTORALLY, not arithmetically. If you were to graph this addition, you would show any resistance voltage in phase with the current, the capacitor voltage at -90 degrees to the current and the inductor voltage at +90 degrees to the current, for a phase difference between them of 180 degrees, cancelling each other out.In a series resonant circuit, the impedances of the capacitor and inductor cancel each other. The only impedance to the flow of current is any resistance in the circuit. Since real-life inductors always have some resistance, at least there is always some resistance in a series resonant circuit.
A voltage or current source in series with a circuit breaker or fuse in series with a switch in series with a light bulb.
The first thing you need to know is the internal resistance of the current source, the voltage source will have the same internal resistance. Then compute the open circuit voltage of the current source, this will be the voltage of the voltage source. You are now done.
A series circuit will work if there is a closed path through which the current can pass, and a voltage source. Otherwise it won't.
Take the internal series resistance of the voltage source and make it the internal parallel resistance of the current source. Then compute using Ohm's law the current of the current source to be equal to the maximum current the original voltage source could supply a short circuit load. Note: the two sources are equivalent.
voltage source and current source
Total voltage = the source. The voltage around the circuit is divided proportionally by each of the resistances in line. The current is = the source voltage divided by the sum of all the resistance.
The voltage between the ends of the circuit doesn't change ... that's where the power source is connected. But when you add more items in a series circuit, the voltage across each item changes. The individual voltages across each item in the series circuit always add up to the voltage of the power source. So in general, if you add more items, the voltage across each of the original ones must drop somewhat.
A: assuming a infinite current source the current will increase accordingly
Compute the open load voltage of the current source across its shunt resistance.This voltage becomes the voltage source's voltage.Move the current source's shunt resistance to the voltage source's series resistance.Insert the new voltage source into the original circuit in place of the current source.
A: By introducing a very small shunt resistance in series with the source and measuring the voltage drop which a meter will translate into current
A voltage source whose voltage varies proportionally to a current flowing through some other path in the circuit.
In an AC circuit, the source voltage can either lead or lag the current, depending on the type of load. Inductive loads cause the voltage to lag the current, while capacitive loads cause the voltage to lead the current.