To find the total power in a series circuit, you can use the formula ( P = V \times I ), where ( P ) is power, ( V ) is voltage, and ( I ) is current. Given a current of 82 mA (which is 0.082 A) and a voltage of 12 V, the calculation would be ( P = 12 V \times 0.082 A = 0.984 W ). Therefore, the total power in the circuit is approximately 0.98 watts.
A voltage or current source in series with a circuit breaker or fuse in series with a switch in series with a light bulb.
The first thing you need to know is the internal resistance of the current source, the voltage source will have the same internal resistance. Then compute the open circuit voltage of the current source, this will be the voltage of the voltage source. You are now done.
Compute the open load voltage of the current source across its shunt resistance.This voltage becomes the voltage source's voltage.Move the current source's shunt resistance to the voltage source's series resistance.Insert the new voltage source into the original circuit in place of the current source.
The question is vague.A current source is the short form of constant current source.A voltage source, on the other hand, is the short form of constant voltage source.That being so, then no, a current source is not available in any circuit.
A series circuit is powered by a voltage source, such as a battery or power supply, which provides the electrical energy needed for the circuit to function. In a series configuration, components are connected end-to-end, so the same current flows through each component. This means that the total voltage of the power source is divided among the components in the circuit. If one component fails or is disconnected, the entire circuit stops functioning.
A voltage or current source in series with a circuit breaker or fuse in series with a switch in series with a light bulb.
The first thing you need to know is the internal resistance of the current source, the voltage source will have the same internal resistance. Then compute the open circuit voltage of the current source, this will be the voltage of the voltage source. You are now done.
A series circuit will work if there is a closed path through which the current can pass, and a voltage source. Otherwise it won't.
Take the internal series resistance of the voltage source and make it the internal parallel resistance of the current source. Then compute using Ohm's law the current of the current source to be equal to the maximum current the original voltage source could supply a short circuit load. Note: the two sources are equivalent.
Total voltage = the source. The voltage around the circuit is divided proportionally by each of the resistances in line. The current is = the source voltage divided by the sum of all the resistance.
voltage source and current source
The voltage between the ends of the circuit doesn't change ... that's where the power source is connected. But when you add more items in a series circuit, the voltage across each item changes. The individual voltages across each item in the series circuit always add up to the voltage of the power source. So in general, if you add more items, the voltage across each of the original ones must drop somewhat.
A: assuming a infinite current source the current will increase accordingly
Compute the open load voltage of the current source across its shunt resistance.This voltage becomes the voltage source's voltage.Move the current source's shunt resistance to the voltage source's series resistance.Insert the new voltage source into the original circuit in place of the current source.
A: By introducing a very small shunt resistance in series with the source and measuring the voltage drop which a meter will translate into current
A voltage source whose voltage varies proportionally to a current flowing through some other path in the circuit.
In an AC circuit, the source voltage can either lead or lag the current, depending on the type of load. Inductive loads cause the voltage to lag the current, while capacitive loads cause the voltage to lead the current.