At resonance, the impedance of L and C completely cancel each other out, so you only have R left. If your circuit does not have any gain, then you should be able to determine the RMS current very easily by looking at the RMS voltage input divided by R.
Series resonance is called voltage resonance because at resonance frequency in a series RLC circuit, the impedance of the inductor and capacitor cancel each other out, resulting in minimum impedance. This causes the total voltage across the circuit to be maximized, leading to a peak in voltage across the components at resonance. This phenomenon is known as voltage resonance because it results in a maximum voltage across the circuit at that specific frequency.
It is 100+j(500-300) ohm = (100+j200) ohm = 223.6<630 ohm
Resistance
Assuming you are talking about an AC circuit, then the total opposition to the flow of current in an R-C circuit is called its impedance (symbol: Z), measured in ohms. This is the vector sum of the circuit's resistance (R) and its capacitive reactance (XC) -each also measured in ohms.
'Reactance' is the name given to the opposition to the flow of alternating current, due to the inductance of a load and the frequency of the supply voltage. It is measured in ohms.
Series resonance is called voltage resonance because at resonance frequency in a series RLC circuit, the impedance of the inductor and capacitor cancel each other out, resulting in minimum impedance. This causes the total voltage across the circuit to be maximized, leading to a peak in voltage across the components at resonance. This phenomenon is known as voltage resonance because it results in a maximum voltage across the circuit at that specific frequency.
In series resonance, the inductance and the capacitance are connected in series, but in parallel resonance they are connected in parallel. In series resonance, at an input signal with a frequency equal to resonance frequency, the total impedance of both inductive and capacitive elements together is zero (or they appear as short circuits) unlike the parallel resonance case in which it is infinite and they appear as an open circuit.
The short circuit capacity of a generator can be calculated by dividing the generator's reactance by the sum of the generator's reactance and the total reactance of the system. This ratio will give you the short circuit capacity of the generator in relation to the total system capacity.
It is 100+j(500-300) ohm = (100+j200) ohm = 223.6<630 ohm
If both were reactances instead of resistances.AnswerIf one impedance was resistive-inductive (R-L) and the other impedance was resistive-capacitive (R-C), then the effective impedance could be less than either. For example, towards or at resonance, the inductive reactance will negate the capacitive reactance, leaving resistance as the main (or only) opposition to current flow. At resonance, the impedance of a circuit is simply its resistance.
Resistance
Assuming you are talking about an AC circuit, then the total opposition to the flow of current in an R-C circuit is called its impedance (symbol: Z), measured in ohms. This is the vector sum of the circuit's resistance (R) and its capacitive reactance (XC) -each also measured in ohms.
Impedance.
'Reactance' is the name given to the opposition to the flow of alternating current, due to the inductance of a load and the frequency of the supply voltage. It is measured in ohms.
The total impedance of a circuit with a capacitor in parallel with a resistor is calculated using the formula Z 1 / (1/R 1/Xc), where Z is the total impedance, R is the resistance of the resistor, and Xc is the reactance of the capacitor. This formula takes into account the combined effects of resistance and reactance in the circuit.
To find the resistance needed in series with the 250 ohms inductive reactance to give a total impedance of 400 ohms, we use the Pythagorean theorem for the impedance triangle in series circuits. Given the inductive reactance (X) = 250 ohms, total impedance (Z) = 400 ohms, and resistance (R) = unknown, we have R² + X² = Z². Substituting the values, we get R = √(Z² - X²) = √(400² - 250²) = √(160000 - 62500) = √97500 ≈ 312.5 ohms. Therefore, approximately 312.5 ohms of resistance should be connected in series with the 250 ohms inductive reactance to achieve a total circuit impedance of 400 ohms.
In a parallel circuit, each branch has its own current path, allowing the total current to be the sum of the currents in each branch. This is why it is known as current magnification. However, at resonance, the impedance in the circuit is at its minimum, causing the total current in the circuit to decrease. This does not change the fact that individual branches can still have higher currents than in a series circuit due to the unique current paths in a parallel arrangement.