The use of the reverse string in C program is used to reverse the letters in the string. An example would be reverse me would be reversed to em esrever.
Assume C#, not C: Traditional way: public string Reverse(string s) { if (string.IsNullOrEmpty(s)) return s; // "" or null char[] characters = s.ToCharArray(); Array.Reverse(characters); return new string(characters); } or as an extension method: public static string Reverse(this string s) { if (s == "") return ""; char[] characters = s.ToCharArray(); Array.Reverse(characters); return new string(characters); } The differences of the 2 methods above is on the caller (how to use Reverse()), and they may co-exist: For example: string test = "abc"; string result1 = Reverse(test); // traditional way string result2 = test.Reverse(); // call the extension
To reverse a number, first convert the number to a string, then reverse the string. Given your number consists of alphanumeric characters, the number must already be a string so simply reverse the string: #include<string> using std::string; string reverse (const string& s) { string str {}; for (auto c : s) str.insert (str.begin(), c); return str; } int main () { std::cout << "Enter a number: "; string s {}; std::cin >> s; std::cout << "The number in reverse is: " << reverse (s); }
wefwfe
C doesn't have String data-type, so don't use it.
Use the following function to count the number of digits in a string. size_t count_digits (const std::string& str) { size_t count = 0; for (std::string::const_iterator it=str.begin(); it!=str.end(); ++it) { const char& c = *it; if (c>='0' && c<='9'); ++count; } return count; }
Assume C#, not C: Traditional way: public string Reverse(string s) { if (string.IsNullOrEmpty(s)) return s; // "" or null char[] characters = s.ToCharArray(); Array.Reverse(characters); return new string(characters); } or as an extension method: public static string Reverse(this string s) { if (s == "") return ""; char[] characters = s.ToCharArray(); Array.Reverse(characters); return new string(characters); } The differences of the 2 methods above is on the caller (how to use Reverse()), and they may co-exist: For example: string test = "abc"; string result1 = Reverse(test); // traditional way string result2 = test.Reverse(); // call the extension
#include #include #include int reverse(int i);char st[]="ven123kat";void main() {printf("\nThe string is: %s", st);reverse(0);printf("\nReversed string is: %s", st);getch();}int reverse(int i) {if (i
Certainly. That's what sequence %s is good for.
To reverse a number, first convert the number to a string, then reverse the string. Given your number consists of alphanumeric characters, the number must already be a string so simply reverse the string: #include<string> using std::string; string reverse (const string& s) { string str {}; for (auto c : s) str.insert (str.begin(), c); return str; } int main () { std::cout << "Enter a number: "; string s {}; std::cin >> s; std::cout << "The number in reverse is: " << reverse (s); }
I'd use sprintf (assuming the number wasn't a string already) and pointers. If that's not enough of a clue, you're really not ready to be in this programming class.
wefwfe
You can use so called concatenation of strings:{...string str1 = "something here";string str2 = " and something here";string newStr = str1 + str2;...}
Use the Exception class and type converters.
C doesn't have String data-type, so don't use it.
Use the following function to count the number of digits in a string. size_t count_digits (const std::string& str) { size_t count = 0; for (std::string::const_iterator it=str.begin(); it!=str.end(); ++it) { const char& c = *it; if (c>='0' && c<='9'); ++count; } return count; }
Use the tolower() function. Example: char* a = 'X'; a = tolower(a); printf("%c", a);
Any character can be used in string, except for \\0. char example [] = "A&B|C";