30 ohms.
The value of a resistor with 5 volts across it and 20 milliamperes of current flowing through it is 250 ohms. Ohm's Law: E = I R R = E/I
It is the same, you can use ohm, µ, R or E to represent Ohm, like 2E2 or 2R2 = 2.2 Ohm and 2K2 = 2.2 Kilo Ohm also 2M2 will be 2.2 Mega Ohm.
We picture the cell as its Thevenin equivalent ... an ideal voltage source ' V ' in series with an internal resistance ' R '. You're asking for the value of ' R '.With the 2-ohm resistor: I = V / (R + 2) = 0.9 ===> V = 0.9 (R + 2)With the 7-ohm resistor: I = V / (R + 7) = 0.3 ===> V = 0.3 (R + 7)Since ' V ' is constant, 0.9 (R + 2) = 0.3 (R + 7)0.9R + 1.8 = 0.3R + 2.10.6R = 0.3R = 0.3 / 0.6 = 1/2 ohmWe can confirm this result either by substitution or by measuring the cell open-circuitly. It should be 2.25 volts.
Ohm's Law is stated as V=I*R, where V = voltage, I = current, R = resistance.
By ohm's law, R = V/I. Given V = 9 V and I = 3 A. Plugging this we get, R = 9/3 = 3 ohm. Hence the resistance value in the circuit is 3 ohm.
Write down the Ohm's law expression of "V = I * R" where "V" is the voltage drop across shunt resistor, "I" is the current flowing through shunt and "R" is the shunt resistance.Substitute value of voltage "V" and current "I" in the Ohm's law expression. For example, if voltage across shunt is 10 volts and current flowing through it is 1 ampere, then the expression is 10 = 100 * R.Divide the expression throughout by 100 to calculate the "R" value. Using a calculator, find the value of "R." From the example, the value of "R" will be 0.1 ohm, which is the value of shunt resistor.
30 ohms.
If the loads are wired in series, add the three values to get the total R. If they are in parallel then the formula is 1/R = 1/R1 + 1/R2 + 1/R3 The total resistane when resistors are in parallel is ALWAYS LESS than the lowest individual value.
Z = SQR (R² + XL²)Where:Z = Impedance (ohm)R = Resistance (ohm)XL= Inductance Reactance (ohm)
Z = SQR (R² + XL²)Where:Z = Impedance (ohm)R = Resistance (ohm)XL= Inductance Reactance (ohm)
The unit for resistance (R) in the International System of Units (SI) is the ohm (Ω).
Power dissipated is always Volts times Amps. W= V*I because of ohm's law, V=I*R, you can substitute either the voltage or amperage with the other value; W= V^2/R or W= I^2*R.
R = rho * L / pi r^2 So L = pi r^2 R / rho r = 0.400 X 10^-3 m R = 100 ohm rho = to be noted in a data book Plugging these known values we can compute the value of length in meter'
56000 ohm or 56 Kilo ohm
V/IXR This helps you to remember the three versions of Ohm's Law: V = I X R R = V/I I = V/R
False. Ohm's law states that V I R, where V is voltage, I is current, and R is resistance.