To determine the value of resistance between b1 and b2, you need to know the specific circuit configuration and the resistances involved. If b1 and b2 are connected through resistors in series or parallel, you can apply the appropriate formulas: for series, ( R_{total} = R_1 + R_2 + ... ); for parallel, ( \frac{1}{R_{total}} = \frac{1}{R_1} + \frac{1}{R_2} + ... ). Without additional information about the circuit, the exact value cannot be determined.
What is the valid class declaration header for the derived class d with base classes b1 and b2?A. class d : public b1, public b2 {/*...*/};B. class d : class b1, class b2 {/*...*/};C. class d : public b1, b2 {/*...*/};D. class d : b1, b2 {/*...*/};The answer is A, C and D.B is not valid because "class" is not a valid access specifier.All the others are valid because private access is the default when the access specifier is omitted. Note that if class D were declared using the struct prefix, inheritance would default to public access rather than private.
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Multiple inheritance occurs when a class is derived directly from two or more base classes. class b1 {}; class b2 {}; class d: public b1, public b2 {}; // multiple inheritance class
Whenever a derived class requires direct inheritance from a base class, even if it inherits that base class indirectly. That is, if V is a base class from which B is derived, and D is derived from B, then D inherits from V indirectly (through B). But if B is virtually derived from V, then D will inherit directly from V. This feature is commonly used in conjunction with multiple inheritance. Examine the following declarations: class V{}; class B1: public V{}; class B2: public V{}; class M: public B1, public B2{}; Now suppose you have the following code: M m; // Declare an instance of M. V& v = m; // Ambiguous... The problem with this is that M inherits V from both B1 and B2, and therefore inherits two separate instances of V. The compiler is unable to determine which instance of V you want to refer to. One solution to this would be to use static casts to indirectly refer to an explicit instance of V: V& v = static_cast<B1&>(m); or V& v = static_cast<B2&>(m); While this is certainly workable, it is an ugly approach that places far too much responsibility upon the programmer to ensure the correct instance of V is being referred to. However, unless there is a specific need to have two instances of V within M, the problem can be resolved with virtual inheritance. By virtually deriving both B1 and B2 from V, M will directly inherit just one instance of V, which is then shared, virtually, between B1 and B2: class V{}; class B1: public virtual V{}; class B2: public virtual V{}; class M: public B1, public B2{}; M m; V& v = m; // No ambiguity. Now M can access all the members of V directly, as can B1 and B2, because they now share the same instance of V. Note that it doesn't matter whether the virtual keyword is placed before or after the access specifier (which is public in this case). "virtual public" and "public virtual" have the same meaning.
Object slicing typically occurs when operating upon a base class reference, even when the reference is actually an instance of a derived class. You might expect polymorphic behaviour but it doesn't happen, due to object slicing. Most of the time this is only to be expected (such as when passing a derived object to a base class copy constructor or assignment operator), but when you actually expect polymorphic behaviour it can catch you out. The following example of partial assignment demonstrates this:#includestruct A {int a_var;A(int a): a_var(a) {}void debug() { std::cout
A B1/B2 visa allows for both business (B1) and tourism (B2) purposes, while a B2 visa is specifically for tourism and visiting friends or family in the United States.
A B2 visa is for tourism or medical treatment, while a B1/B2 visa allows for both business and tourism purposes.
A B1 visa is for business purposes, while a B2 visa is for tourism or medical treatment.
A B1 visa is for business travel, while a B2 visa is for tourism or visiting family and friends.
A B1 visa is for business travel, while a B2 visa is for tourism or visiting family and friends.
No, you cannot work on a B1/B2 visa.
Yes, you can work on a B1/B2 visa.
No, a B1/B2 visa does not allow you to work in the USA.
To show all possible interleavings of two processes, let’s assume we have two atomic statements from Process A (A1, A2) and Process B (B1, B2). The possible interleavings could be: A1, A2, B1, B2 A1, B1, A2, B2 B1, A1, A2, B2 A1, B2, A2, B1 B1, B2, A1, A2 B2, A1, A2, B1 A2, A1, B1, B2 B2, B1, A1, A2 These interleavings illustrate the various ways the two processes can be executed in a concurrent setting.
A B1/B2 visa is typically valid for 10 years.
A B1/B2 visa is typically valid for 10 years.
A B1/B2 visa allows for both business (B1) and tourism (B2) purposes, while a B2 visa is solely for tourism. The distinction impacts the activities allowed, with B1/B2 visa holders able to engage in business-related activities in addition to tourism, while B2 visa holders are limited to tourism activities only.