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I(current) = V(voltage)/R(resistence) Example : 220 V / 5000 Ohm = 0.044 A (Ampère) = 44mA
What else can I help you with?
If a ac circuit was a captive circuit you would know that in that circuit the current?
In a capacitive circuit, you must first calculate the capacitive reactance (Xc) This is done by 2 x Pi x frequency x the value of capacitor. Then divide one by the answer. This will give you the capacitive reactance in ohms. You can then apply ohms law to find the current. So eg: A 10 ohm resistor is in series with a 150micro farad capacitor across a 230v 50Hz supply. find circuit current. So 2 x pi x 50 x 150E-6(means x10-6 on calc) 2 x 3.14159... x 50 150e-6 = 0.047123889(ans) Now 1/Ans = 21.22 ohms. So you can now add the 21.22 ohms and the 10 ohms together giving 31.22 ohms. This is the total circuit resistance. Now apply ohms law I = V/R So I = 230/31.22 = 10.83 Amps!
Why in a circuit using power I equals Watts divided by Volts when you increase voltage the current will reduce so why does this differ from Ohms law when you increase voltage the current increases?
When you increase voltage (V) then, to get the same total power (W), the current (I) must be decreased. This result comes from the Power Law: Power = voltage x current Ohms Law does not deal with power at all, it deals only with the relationship between voltage, resistance and current: Voltage = resistance x current
What value must be known to determine the current in a complex circuit?
To determine the current in a complex circuit, you must know the total voltage supplied by the power source and the total resistance of the circuit. Using Ohm's Law (I = V/R), where I is the current, V is the voltage, and R is the resistance, you can calculate the current flowing through the circuit. Additionally, if the circuit is alternating current (AC), knowing the impedance is also essential.
A electric heater works by passing a current of 100 A through a coiled metal wire making it red hot if the resistance of the wire is 1.1 ohms what voltage must be applied to it?
Volts = Amps * ohms 110 = 100*1.1 Thus the voltage was 110 Volts.
Can the amperage of a DC current be increased keeping the voltage constant?
According to Ohms law, current will increase in proportion to the voltage increase. Ohms law is an equation:Voltage = current x resistance.If the resistance stays the same, any increase in voltage must mean a proportional increase in current according to this equation.
What must know to calculate current using Ohms law?
The resistance R in ohms (Ω) is equal to the voltage V in volts (V) divided by the current I in amps (A)
How do you find resistance when you have current and resistance total?
If you are looking for the resistance of each resistor in either a series circuit or a parallel circuit you must measure the current I and the voltage V for each resistor. Then calculate its resistance using Ohms Law R = V / I where I = current (Amps), V = voltage (Volts) and R= resistance (Ohms).
A circuit has total resistance of 5 ohms and a current of 0.3 amperes What voltage must the battery supply?
1.5 volts
Do multiply or divide convert kohms to ohms?
Ohms are smaller than k-ohms, so number of ohms must be a bigger number. Multiply k-ohms by 1,000 to get the same resistance in ohms.
What are the parts of an electrical current?
A flow of electrons is needed to have a current. And there (usually) must be a complete circuit. And you need a voltage to make the current move around your circuit. All tied up in Ohms Law - which I'll leave to you.
How do you know that the sensor is bad?
Find out the ohms range it must be within and do an ohms test.
What scale must a dmm have to measure current in a circuit?
A digital multimeter (DMM) must have a current measurement scale appropriate for the expected current in the circuit. Choose a scale that is equal to or higher than the maximum expected current in the circuit to ensure accurate measurements and to prevent damage to the DMM.
If a ac circuit was a captive circuit you would know that in that circuit the current?
In a capacitive circuit, you must first calculate the capacitive reactance (Xc) This is done by 2 x Pi x frequency x the value of capacitor. Then divide one by the answer. This will give you the capacitive reactance in ohms. You can then apply ohms law to find the current. So eg: A 10 ohm resistor is in series with a 150micro farad capacitor across a 230v 50Hz supply. find circuit current. So 2 x pi x 50 x 150E-6(means x10-6 on calc) 2 x 3.14159... x 50 150e-6 = 0.047123889(ans) Now 1/Ans = 21.22 ohms. So you can now add the 21.22 ohms and the 10 ohms together giving 31.22 ohms. This is the total circuit resistance. Now apply ohms law I = V/R So I = 230/31.22 = 10.83 Amps!
In Ohm law what must be greater to maintain the same current in a conductor with more resistance?
ohms law states V = I*R. If I is to remain the same, and R is increased, the voltage must also increase.
What will be the temperature of a resistive wire 8 ohms when a 1ampere passes through it at 1 volt?
Trick question. From Ohms law resistance equals voltage over current (R=V/A). To get 1 ampere at 1 volt the resistance must be 1 ohm!
Why in a circuit using power I equals Watts divided by Volts when you increase voltage the current will reduce so why does this differ from Ohms law when you increase voltage the current increases?
When you increase voltage (V) then, to get the same total power (W), the current (I) must be decreased. This result comes from the Power Law: Power = voltage x current Ohms Law does not deal with power at all, it deals only with the relationship between voltage, resistance and current: Voltage = resistance x current
What value must be known to determine the current in a complex circuit?
To determine the current in a complex circuit, you must know the total voltage supplied by the power source and the total resistance of the circuit. Using Ohm's Law (I = V/R), where I is the current, V is the voltage, and R is the resistance, you can calculate the current flowing through the circuit. Additionally, if the circuit is alternating current (AC), knowing the impedance is also essential.
