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On a standby generator 100 percent of the power drops before the generator will start.

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โˆ™ 2013-12-01 06:41:24
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Q: What percent of power drops before generator starts?
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What does 50 hertz or 60 hertz mean in an electrical generator?

The unit hertz means "cycles per second" and is a measure of the frequency of variation of anything which changes during a set period of time, including electric current and voltage. Saying that a generator of electricity runs at 50 hertz means that its current and voltage changes regularly at a rate of 50 times per second. Saying that a generator of electricity runs at 60 hertz means that its current and voltage changes regularly at a rate of 60 times per second. The Hertz value can be changed on the generator by increasing or decreasing the speed (RPM) of the prime mover. The generator has a feed back unit that monitors the frequency and automatically applies more power to the prime mover if the load increases and the generator RPM starts to slow down. The reverse happens if the load drops off and the generator starts to speed up, the power to the prime mover will be reduced. On a diesel generator it is the fuel flow that is increased and decreased to keep the frequency at a constant value. On a water turbine it is the water flow that is increased and decreased to keep the frequency at a constant value.

For resistances in a series circuit how are the voltage drops across the resistance related to the total voltage?

The voltage drops across each resistance sum to the total voltage.

Why terminal voltage of the self-excited shunt generator lower than that of the separately excited shunt generato?

Some generators are self excited; this means their terminal voltage is fed back to the excitation system to supply power to the rotor of the generator (which makes it into an electromagnet); the more power that is fed back, the stronger the electromagnet becomes, which makes it harder to turn the generator, which causes the generator to push out more power (simplified, really quick version). If there is a fault electrically near the terminal of a self excited generator, the terminal voltage will sage to near zero; this means the voltage supplied to the excitation system will drop by the same percentage (say the terminal voltage is 30% of what it should be, then the maximum supplied voltage to the excitation system drops to 30% of what it normally is, since P = V*I). Since the input power is less, the output of the generator will decrease (current will decrease). The terminal voltage is determined by the impedance between the generator and the fault such that V = I*Z; As I decreases, V will also continue to fall, causing the terminal voltage to sag even more. A non-self excited generator gets its' excitation power from the grid, specifically from a location that is electrically separated from its' terminal voltage. If the terminal voltage sagged to 30% (same fault location as above example), the excitation system voltage may be impacted slightly (say 2%) so the excitation system power is near maximum (98% for this example). Since the excitation system is much farther removed from the terminal voltage, it is not dependent upon it, thus the terminal voltage will not continue to sag as with a self excited system.

When two alternator running in parallel the power factor from 8 drops to 5 or less why is it so?

power factor 0.8 drops to .05 when two alternator running in parallel

How do you make a candy DNA Model?

out of licorice and gum drops

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