A 100 ohm resistor carrying a current of 0.3 amperes would, by Ohm's Law, have a potential difference of 30 volts. A current of 0.3 amperes through a voltage of 30 volts would, by the Power Law, dissipate a power of 9 watts. You need a 10 watt resistor, alhough it is better to use a 20 watt resistor. E = IR 30 = (0.3)(100) P = IE 9 = (30)(0.3)
To drop a 12 volt source to 6 volts with a resistor, you have to drop 6 volts. The value of the resistor you need would be 6 divided by the current the device pulls in amps. For example, if the device pulls a half an amp the resistor has to be 6/0.5 or 12 ohms. As this device runs on 6 volts and draws 1/2 amp, it's wattage is 3 watts (volts x Amps). Common practice is to double this, or the resistor will probably get too hot and may open. I'd use a 10 watt to resistor to maintain a good margin for safety, and they're readily available. Use a 12 ohm, 10 watt resistor.
Internal capacitance of transistor increases propagation delay.Because charging and discharging of these capacitors will take more time which is not favourable.So always try to select transistors with minimum capacitance.
The amount of current (amps) is controlled by the user. It's done with a variable resistor. Another thing to note is whether you are welding constant current or constant voltage. If you are welding constant current, the voltage will vary and a set Amp measure will remain constant. With constant voltage, the current will vary and that's determined by the resistance. Constant voltage should be an easier set up. I'm not 100% sure but most stick welding is constant current, which is why increasing the arc length produces more heat, because more arc length should increase the resistance, which would cause the welding machine to increase voltage to keep the current constant.
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The resistor color code use to help to identify the resistance of the resistor. There are four color in the resistor that help to identify the resistance of the resistor. The first and second color represent the numerical value of the resistor. The third color represent the multiplier. The four color represent the tolerance.
count up the value of the resistor using the colour bands along with resistor code chart(or it may on the resistor eg. 10kohms, follow this by hooking up an ohm meter(you will have to select ohms, kilo-ohms, mega-ohms whichever applies) , your resistance should appear within the acceptable variable guidelines.. usually 5 to 10 percent(last band or on the resistor itself) count up the value of the resistor using the colour bands along with resistor code chart(or it may on the resistor eg. 10kohms, follow this by hooking up an ohm meter(you will have to select ohms, kilo-ohms, mega-ohms whichever applies) , your resistance should appear within the acceptable variable guidelines.. usually 5 to 10 percent(last band or on the resistor itself)
You can measure directly with an Ohm Meter, often combined with a Volt Meter. Or you can measure the voltage across the resistance and the current to calculate resistance as Current divided by Voltage.
Voltage drop is the product of current and resistance. When you connect a voltmeter across a resistor, you are connecting that voltmeter's internal resistance in parallel with that resistor. The resulting resistance of this parallel combination is lowerthan that of the resistor. As a result the voltage drop (current times this lower resistance) will be lower than it would be without the voltmeter connected. This is called the 'loading effect' of that voltmeter.The higher the internal resistance of the voltmeter, the less effect it will have on lowering the overall resistance when connected across a resistor. This is why the internal resistance of a voltmeter is made deliberately very high. Under most circumstances, therefore, a conventional voltmeter will have very little effect on the resistance of the circuit being tested and, so, it will have no significant effect on the voltage appearing across the resistor.However... for circuits that already have exceptionally-high resistance values, you must be careful when you select a voltmeter as you must take into account its internal resistance and ensure the voltmeter you use has the very highest internal resistance available. This is because the loading effect increases with circuits that have a high resistance. That might involve selecting a voltmeter that works on a completely-different principle , such as an electrostatic voltmeter or, perhaps, an oscilloscope
Durg resistance
The Name Box, beside the formula bar, allows you to select a cell by entering its cell address.The Name Box, beside the formula bar, allows you to select a cell by entering its cell address.The Name Box, beside the formula bar, allows you to select a cell by entering its cell address.The Name Box, beside the formula bar, allows you to select a cell by entering its cell address.The Name Box, beside the formula bar, allows you to select a cell by entering its cell address.The Name Box, beside the formula bar, allows you to select a cell by entering its cell address.The Name Box, beside the formula bar, allows you to select a cell by entering its cell address.The Name Box, beside the formula bar, allows you to select a cell by entering its cell address.The Name Box, beside the formula bar, allows you to select a cell by entering its cell address.The Name Box, beside the formula bar, allows you to select a cell by entering its cell address.The Name Box, beside the formula bar, allows you to select a cell by entering its cell address.
The size of the resistor will depend on the load. Let's look at this a bit to see if we can make sense of it. You want to drop the applied voltage to a device from 12 volts AC to 11 volts AC. That means you want to drop 1/12th of the applied voltage (which is 1 volt) across the resistor so that the remaining 11/12ths of the applied voltage (which is 11 volts) will appear across the load. The only way this is possible is if the resistor has 1/11th of the resistance of the load. Here's some simple math. If you have an 11 ohm load and a 1 ohm resistor in series, you'll have 12 ohms total resistance ('cause they add). If 12 volts is applied, the 1 ohm resistor will drop 1 volt, and the 11 ohm load will drop the other 11 volts. A ratio is set up here in this example, and each ohm of resistance will drop a volt (will "feel" a volt) across it. See how that works? If the resistance of the load is 22 ohms and the resistance of the (series) resistor is 2 ohms, each ohm of resistance will drop 1/2 volt, or, if you prefer, each 2 ohms of resistance will drop 1 volt. The same thing will result, and the load will drop 11 volts and the series resistance will drop 1 volt. That's the math, but that's the way things work. You'll need to know something about the load to select a series resistance to drop 1/12th of the applied voltage (which is 1 volt) so your load can have the 11 volts you want it to have. There is one more bit of news, and it isn't good. If your load is a "dynamic" one, that is, if its resistance changes (it uses more or less power over the time that it is "on"), then a simple series resistor won't allow you to provide a constant 11 volts to that load. What is happening is that the effective resistance of the load in changing over time, and your resistor can't "keep up" with the changes. (The resistor, in point of fact, can't change its resistance at all.) You've got your work cut out for you figuring this one out.
Well, the fan switch... if it has, say, four settings, then the first three settings simply select which resistor the current runs through, and the fourth typically is a circuit with no resistor.
software
it allows you to select certain data
You are referring to the Microsoft Access Database. This allows you the ability to select specific information from one or many tables.
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