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In a series circuit...
Kirchoff's current law: The sum of the signed currents entering a node is zero. Since a series circuit consists of only nodes each connected to only two elements, this means that the current in every point in a series circuit is the same.
Kirchoff's voltage law: The sum of the signed voltage drops in a series circuit is zero. This means, that if you segregate the sources from the loads, the total voltage across all the nodes is equal to the total voltage across all the sources.
That may seem trite, but take the case where you have one battery in series with two resistors also in series. If you know the voltage across one resistor, then you know the voltage across the other resistor - it is the battery voltage minus the first resistor's voltage.
Ohm's law: Voltage is current times resistance. This actually applies everywhere; series circuits, parallel circuits, DC circuits, AC circuits, etc.
What else can I help you with?
In a series circuit each device that is added to circuit decreases the?
Ohm's Law answers your question. Voltage = Current x Resistance. In a series circuit you are in effect adding resistance. If the Voltage remains constant then the answer is obvious looking at the equation above.
How do you lower the current?
To lower the current in a circuit, you can increase the resistance using Ohm's Law (I = V/R), where I is the current, V is the voltage, and R is the resistance. Alternatively, you can reduce the voltage supplied to the circuit, which will also decrease the current. Additionally, adding resistors in series will increase the total resistance and thus lower the current flowing through the circuit.
What happens to the overall resistance of a circuit when too many appliances are connected across a 120 V outlet?
This is a very technical electrical question that may be difficult to understand without further study. But adding appliances to an outlet is the same as adding resistance in parallel. Adding resistance in parallel, the resistance of the circuit goes down. That is why you get more current flow. By contrast, adding resistance in series increases the resistance of the circuit and therefore reduces current, all else being equal.
What happens to the overall current of the circuit if the number of receivers?
If the number of receivers in a circuit increases, the overall current can be affected depending on how the receivers are arranged. In a parallel circuit, adding more receivers generally decreases the total resistance, which can increase the overall current if the voltage remains constant. In a series circuit, adding more receivers increases the total resistance, leading to a decrease in overall current. Therefore, the effect on current depends on whether the receivers are connected in series or parallel.
Is this true or false the more cells there are in a circuit the bigger the push and the current?
False. The number of cells in a circuit does not inherently increase the current; instead, it typically increases the voltage. Current is influenced by both voltage and resistance in the circuit according to Ohm's Law (I = V/R). However, adding more cells in series raises voltage, which can lead to a higher current if the resistance remains constant.
What happens to supply voltage if additional resistance is connected in parallel circuit?
The supply voltage in a parallel circuit remains the same regardless of the number of additional resistors connected. The voltage across each resistor in a parallel circuit is the same as the supply voltage. Adding more resistors in parallel will increase the total current drawn from the supply.
In a series circuit each device that is added to circuit decreases the?
Ohm's Law answers your question. Voltage = Current x Resistance. In a series circuit you are in effect adding resistance. If the Voltage remains constant then the answer is obvious looking at the equation above.
In a series circuit each device that is added to the circuit decreases the?
Ohm's Law answers your question. Voltage = Current x Resistance. In a series circuit you are in effect adding resistance. If the Voltage remains constant then the answer is obvious looking at the equation above.
In a series circuit when adding light bulbs does the current change?
Yes. The current is inversely proportional to the resistance. I = V / R where I is current, V is voltage, and R is resistance. Adding light bulbs adds resistance. Current is constant throughout a series circuit; it doesn't change no matter what. Voltage changes.
In series circuit each device that's added to the circuit decreases the?
Ohm's Law answers your question. Voltage = Current x Resistance. In a series circuit you are in effect adding resistance. If the Voltage remains constant then the answer is obvious looking at the equation above.
Which of the following condition exist in a circuit of pure resistance?
in a circuit of pure Resistance (r), IE. voltage source (12 v DC battery) and pure resistance (a light bulb). the voltage (v) and current (i) will be in phase. by adding capacitors and/or inductors to the circuit V and I will be pulled out of phase.
If the resistance in the circuit is increased what will happen to the current and voltage?
* resistance increases voltage. Adding more resistance to a circuit will alter the circuit pathway(s) and that change will force a change in voltage, current or both. Adding resistance will affect circuit voltage and current differently depending on whether that resistance is added in series or parallel. (In the question asked, it was not specified.) For a series circuit with one or more resistors, adding resistance in series will reduce total current and will reduce the voltage drop across each existing resistor. (Less current through a resistor means less voltage drop across it.) Total voltage in the circuit will remain the same. (The rule being that the total applied voltage is said to be dropped or felt across the circuit as a whole.) And the sum of the voltage drops in a series circuit is equal to the applied voltage, of course. If resistance is added in parallel to a circuit with one existing circuit resistor, total current in the circuit will increase, and the voltage across the added resistor will be the same as it for the one existing resistor and will be equal to the applied voltage. (The rule being that if only one resistor is in a circuit, hooking another resistor in parallel will have no effect on the voltage drop across or current flow through that single original resistor.) Hooking another resistor across one resistor in a series circuit that has two or more existing resistors will result in an increase in total current in the circuit, an increase in the voltage drop across the other resistors in the circuit, and a decrease in the voltage drop across the resistor across which the newly added resistor has been connected. The newly added resistor will, of course, have the same voltage drop as the resistor across which it is connected.
How do you lower the current?
To lower the current in a circuit, you can increase the resistance using Ohm's Law (I = V/R), where I is the current, V is the voltage, and R is the resistance. Alternatively, you can reduce the voltage supplied to the circuit, which will also decrease the current. Additionally, adding resistors in series will increase the total resistance and thus lower the current flowing through the circuit.
In a series circuit each device that is added to the circuit decreases the what?
Depends on the device. If it is a resistor and you have a fixed voltage then the circuit will obey Ohms law. Voltage = Current x Resistance. So if R increases by adding more resistors in series and the voltage is constant, the current will decrease.
What happens to the overall resistance of a circuit when too many appliances are connected across a 120 V outlet?
This is a very technical electrical question that may be difficult to understand without further study. But adding appliances to an outlet is the same as adding resistance in parallel. Adding resistance in parallel, the resistance of the circuit goes down. That is why you get more current flow. By contrast, adding resistance in series increases the resistance of the circuit and therefore reduces current, all else being equal.
What happens to the overall current of the circuit if the number of receivers?
If the number of receivers in a circuit increases, the overall current can be affected depending on how the receivers are arranged. In a parallel circuit, adding more receivers generally decreases the total resistance, which can increase the overall current if the voltage remains constant. In a series circuit, adding more receivers increases the total resistance, leading to a decrease in overall current. Therefore, the effect on current depends on whether the receivers are connected in series or parallel.
Is this true or false the more cells there are in a circuit the bigger the push and the current?
False. The number of cells in a circuit does not inherently increase the current; instead, it typically increases the voltage. Current is influenced by both voltage and resistance in the circuit according to Ohm's Law (I = V/R). However, adding more cells in series raises voltage, which can lead to a higher current if the resistance remains constant.
