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It means to explicitly convert to a certain type.

double a = 5.0;
int b;
b = (int) a;

The (int) is the explicit typecast in this case, but any type can be used, including a user-defined type (i.e., a class name). If you omit it, the compiler will complain, because when you convert a double to an int, precision may be lost. If you include it, you override this compiler check - you basically tell the compiler that you know what you are doing.

It means to explicitly convert to a certain type.

double a = 5.0;
int b;
b = (int) a;

The (int) is the explicit typecast in this case, but any type can be used, including a user-defined type (i.e., a class name). If you omit it, the compiler will complain, because when you convert a double to an int, precision may be lost. If you include it, you override this compiler check - you basically tell the compiler that you know what you are doing.

It means to explicitly convert to a certain type.

double a = 5.0;
int b;
b = (int) a;

The (int) is the explicit typecast in this case, but any type can be used, including a user-defined type (i.e., a class name). If you omit it, the compiler will complain, because when you convert a double to an int, precision may be lost. If you include it, you override this compiler check - you basically tell the compiler that you know what you are doing.

It means to explicitly convert to a certain type.

double a = 5.0;
int b;
b = (int) a;

The (int) is the explicit typecast in this case, but any type can be used, including a user-defined type (i.e., a class name). If you omit it, the compiler will complain, because when you convert a double to an int, precision may be lost. If you include it, you override this compiler check - you basically tell the compiler that you know what you are doing.

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