It means to explicitly convert to a certain type.
double a = 5.0;
int b;
b = (int) a;
The (int) is the explicit typecast in this case, but any type can be used, including a user-defined type (i.e., a class name). If you omit it, the compiler will complain, because when you convert a double to an int, precision may be lost. If you include it, you override this compiler check - you basically tell the compiler that you know what you are doing.
It means to explicitly convert to a certain type.
double a = 5.0;
int b;
b = (int) a;
The (int) is the explicit typecast in this case, but any type can be used, including a user-defined type (i.e., a class name). If you omit it, the compiler will complain, because when you convert a double to an int, precision may be lost. If you include it, you override this compiler check - you basically tell the compiler that you know what you are doing.
It means to explicitly convert to a certain type.
double a = 5.0;
int b;
b = (int) a;
The (int) is the explicit typecast in this case, but any type can be used, including a user-defined type (i.e., a class name). If you omit it, the compiler will complain, because when you convert a double to an int, precision may be lost. If you include it, you override this compiler check - you basically tell the compiler that you know what you are doing.
It means to explicitly convert to a certain type.
double a = 5.0;
int b;
b = (int) a;
The (int) is the explicit typecast in this case, but any type can be used, including a user-defined type (i.e., a class name). If you omit it, the compiler will complain, because when you convert a double to an int, precision may be lost. If you include it, you override this compiler check - you basically tell the compiler that you know what you are doing.
There is no sizeOf() operator in Java.
Java does not support opperator overloading, so the answer to your question is: none.
In Java, the multiplication operator is represented by the asterisk, "*". This was not invented by Java; most programming languages, as well as programs such as Excel, use the same symbol.
with new operator
No, there is no such operator or function in Java that can tell you the amount of memory an object uses.
You type it in with your keyboard.
with help of type casting it is possible
There is no sizeOf() operator in Java.
Java does not have the sizeOf() operator or any operator that gives an equivalent result.
Type casting is used to convert from one datatype to the other
Java does not support opperator overloading, so the answer to your question is: none.
Java does not support user defined operator overloading.The operator '+' is overloaded in Java and can be used for adding both numbers and Strings.
An operator is a symbol that does something in Java. for ex: "+" is an arithmetic operator that adds two numbers. ">" is a logical operator that checks if one number is greater than the other. There are many different types of operators in Java like Arithmetic, Logical, Relational and Assignment operators
In Java, the multiplication operator is represented by the asterisk, "*". This was not invented by Java; most programming languages, as well as programs such as Excel, use the same symbol.
"==" in java is the binary operator which compares two values and gives a boolean result While "=" in java is a assignment operator which assigns a value to a variable.
Type casting exists to allow the use of base class or base interface reference but yet if you know that the object in hand is aspecific derived class, you can typecast and access methods available only in the derived class.
conditional operator , size of operator , membership operator and scope resulation operator can not be overload in c++