A for loop.
I don't specifically know Ruby on Rails, but usually (in most programming languages), to do this task you would define one variable for the sum, and one for a counter. You initialize the sum to zero, and then, in a loop, you (1) increment the counter (most languages specifically have a "for" loop for this), and (2) add the counter to the sum. Here is the pseudocode; it is NOT for a specific programming language, but it gives you the general idea; you should be able to adapt it to most programming languages: sum = 0 for addend = 1 to 10 { sum = sum + addend } output "Sum = ", sum Note that you may also need to initialize the variables, depending on the language.
For
If it isn't, then you don't know for sure what value it will start at in some languages. Thus, your count will be wildly inaccurate. In other languages, it will just generate an error if you forget to initialize. Two steps: 1. It is critical that variables be properly initialized. 2. Counter-variables are variables.
// set up reader BufferedReader reader = new BufferedReader(new InputStreamReader( System.in)); // number of line to read int numberOfLines = 3; // initialize the counter for number of characters int numberOfChars = 0; // prompt user to enter the lines of text System.out.format("Enter %d lines of text:\n", numberOfLines); for (int i = 0; i < numberOfLines; i++) { String line = reader.readLine(); // increment the counter with the number of characters entered in current line numberOfChars += line.length(); } // print the number of characters entered System.out.println("Number of characters entered: " + numberOfChars);
Counter is a digital circuit which is able to count from a specific number to another specific number (according to the requirement). Depending upon the counting style the counters can be divided into two. i) UP counter- which increment one by one (eg. 0,1,,2,3,4,5............15) for a 4 bit counter ii) Down counter- which decrements one by one (eg. 15,14,13,12,11,10,9,8................0) for a 4 bit counter. A simple apllication of a counter is a diigital clock, having 3 counters. One for counting the seconds, another for counting the minute and the last one for counting the hour.
for loop
Test initialize increment
Test initialize increment
I don't specifically know Ruby on Rails, but usually (in most programming languages), to do this task you would define one variable for the sum, and one for a counter. You initialize the sum to zero, and then, in a loop, you (1) increment the counter (most languages specifically have a "for" loop for this), and (2) add the counter to the sum. Here is the pseudocode; it is NOT for a specific programming language, but it gives you the general idea; you should be able to adapt it to most programming languages: sum = 0 for addend = 1 to 10 { sum = sum + addend } output "Sum = ", sum Note that you may also need to initialize the variables, depending on the language.
For
Oh, dude, to find out if a number is positive or negative on an 8085 microprocessor, you can use the sign flag (SF) in the flags register. If the sign flag is set, it means the number is negative. So, like, just check if the SF is 1, and you've got your answer. Easy peasy lemon squeezy!
A counter variable is "incremented" (the step number, 1 in this case, is added to it) in any of the following four ways: $counter = $counter + 1;$counter += 1; //this is shorthand for the above $counter++; //postfix increment operator $counter = 0;echo $counter++;The output would be 0++$counter; //prefix increment operator $counter = 0; echo ++$counter;The output is 1
For
A) Subtract 6 from 48. If the result less than 6 or 0 you made a mistake. Result is 42. Hence start a counter with a value of 1. B) Subtract 6 from 42. If the result less than 6 or 0 you made a mistake. Result is 36. Hence increment the counter by 1. Now counter value is 2. C) Subtract 6 from 36. If the result less than 6 or 0 you made a mistake. Result is 30. Hence increment the counter by 1. Now counter value is 3. D) Subtract 6 from 30. If the result less than 6 or 0 you made a mistake. Result is 24. Hence increment the counter by 1. Now counter value is 4. E) Subtract 6 from 24. If the result less than 6 or 0 you made a mistake. Result is 18. Hence increment the counter by 1. Now counter value is 5. F) Subtract 6 from 18. If the result less than 6 or 0 you made a mistake. Result is 12. Hence increment the counter by 1. Now counter value is 6. G) Subtract 6 from 12. If the result less than 6 or 0 you made a mistake. Result is 6. Hence increment the counter by 1. Now counter value is 7. H) Subtract 6 from 6. If the result is not 0 you made a mistake. Result is 0. Hence increment the counter by 1. Now counter value is 8. Since we have nothing more to subtract from stop the process. The last value of the counter was 8 and so the quotient is 8.
Bleaching is the most common hiding trick. There are bleaches specifically designed for the face, available at the cosmetics counter of your local grocery.
public static void main(String args){ int counter = 0; //initialize the counter variable to 0 while (counter < 10){ //while the counter variable is less than 10... counter ++; //increase the counter variable by 1 System.out.println(counter); //print the counter variable } }
To create a flowchart for calculating the product of the first ten odd numbers, begin with a start symbol, then initialize a variable for the product and a counter at 1. Use a loop structure to multiply the current product by the odd number (which can be calculated as 2n - 1 where n is the counter) and increment the counter until it reaches 10. Finally, display the product and use an end symbol to conclude the process. This flowchart visually represents the steps and decisions involved in the calculation.