It doesn't.
Try this
#include <stdio.h>
#include <wchar.h>
int main (void) {
printf ("sizeof (char)=%d, sizeof (wchar_t)=%d\n",
(int)sizeof (char), (int)sizeof (wchar_t));
return 0;
}
it may require a large amount of data to be read,processed and also served for latter use.such memory is store ion the auxiliary memory device in form of data file.the data file is collection of bytes.
malloc
A java.util.Date object will take about 32 bytes in memory.
A pointer holds a memory address, from 0 to the upper limit of your memory (in 32 bit addressing this is up to 2^32, 64 bit is up to 2^64 bytes). So in math terms, a pointer could be considered a non-negative integer. However this is not the same as the integer type used in C and other languages, which refers to how the data at that memory address (the raw bits) is interpreted by the system. So the expression "int *x;" declares a pointer to an integer, but x is a memory address, not a literal C-style integer. The value pointed to by x, however, will be interpreted as a literal C-style integer. It may be easier to see using a pointer to a char: char character = 'C'; char *pointerToCharacter = character; In this case, character is a standard char variable, and pointerToCharacter is a pointer (which is a memory address) that points to the location in memory of a character.
A single-byte type of array has 1 byte per character; a wide-character array has 2 bytes per character of storage. Without seeing the exact definition it cannot be determined what the actual size of the array would be.
character constant is 4 bytes explanation is all constants is integer
2147483648 bytes
Its the same. The unit for memory is bytes.
Bytes are what computers use for memory. They store digital information that the computer uses.Example: An average song is about 6 megabytes or roughly 6000000 bytes
4 bytes
a) To provide a memory capacity of 4096 bytes using 256x8 RAM chips, you need 4096 bytes / 256 bytes per chip = 16 chips. b) Each memory address for the 256 locations in a chip will require 8 bits (since 2^8 = 256). Therefore, each chip will require 8 address lines to select one of the 256 locations.
A kilobyte (or a k) is 1024 bytes, so 16k is 16*1024 bytes or 16384 bytes.
Approximately 512 bytes. About enough to store a 500 character plain text file.
bytes are used to represent the amount of capacity in a memory
The memory in the computer is stored in the form of bits and bytes
4,096 In computer memory, "kilo" refers to 2 to the 10th power, or 1024, rather than to 1000.
15,383 Bytes