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How the charges on opposing plates of a capacitor compare?
In a capacitor, the charges on the opposing plates are equal in magnitude but opposite in sign. This means that if one plate has a positive charge, the other plate will have an equivalent negative charge. This separation of charge creates an electric field between the plates, allowing the capacitor to store electrical energy. The relationship between the charges and the capacitance is described by the formula ( Q = C \cdot V ), where ( Q ) is the charge, ( C ) is the capacitance, and ( V ) is the voltage across the plates.
What is function of second plate in a parallel plate capacitor?
In a parallel plate capacitor, the second plate serves to create an electric field between the two plates when a voltage is applied. This configuration allows the capacitor to store electrical energy in the electric field created between the plates. The separation and area of the plates, along with the dielectric material (if present), determine the capacitor's capacitance, which indicates its ability to store charge. Essentially, the second plate works in conjunction with the first plate to facilitate charge separation and energy storage.
How much charge is held on one plate of a 15 farad capacitor brought to 6v?
The charge stored on a capacitor can be calculated using the formula ( Q = C \times V ), where ( Q ) is the charge in coulombs, ( C ) is the capacitance in farads, and ( V ) is the voltage in volts. For a 15 farad capacitor charged to 6 volts, the charge is ( Q = 15 , \text{F} \times 6 , \text{V} = 90 , \text{C} ). Therefore, one plate of the capacitor holds 90 coulombs of charge.
How much charge is on each plate of a 12.7mf capacitor that has been charged by 120.0 V potential difference?
To find the charge on each plate of a capacitor, use the formula ( Q = C \times V ), where ( Q ) is the charge, ( C ) is the capacitance, and ( V ) is the potential difference. For a 12.7 µF (microfarads) capacitor charged to 120.0 V, first convert capacitance to farads: ( 12.7 , \text{µF} = 12.7 \times 10^{-6} , \text{F} ). Then, calculate the charge: ( Q = 12.7 \times 10^{-6} , \text{F} \times 120.0 , \text{V} = 1.524 , \text{mC} ) (milliCoulombs). Thus, each plate has a charge of approximately 1.524 mC.
What is the ratio between the charge on either plates of capacitor and the potential difference between the plate?
The ratio between the charge on either plate of a capacitor (Q) and the potential difference (V) across the plates is given by the capacitance (C) of the capacitor, expressed as ( C = \frac{Q}{V} ). This means that the capacitance is a measure of how much charge a capacitor can store per unit of voltage applied. Therefore, the ratio ( \frac{Q}{V} ) is constant for a given capacitor and is equal to its capacitance.
Does a charged capacitor have an identical level of charge on both plates?
No, in a charged capacitor, one plate has a positive charge and the other plate has a negative charge. The magnitude of the charges on the plates is equal and opposite, resulting in a net charge of zero for the entire capacitor.
How the charges on opposing plates of a capacitor compare?
In a capacitor, the charges on the opposing plates are equal in magnitude but opposite in sign. This means that if one plate has a positive charge, the other plate will have an equivalent negative charge. This separation of charge creates an electric field between the plates, allowing the capacitor to store electrical energy. The relationship between the charges and the capacitance is described by the formula ( Q = C \cdot V ), where ( Q ) is the charge, ( C ) is the capacitance, and ( V ) is the voltage across the plates.
Can you change your license plate number if you are not happy with it at no additional charge?
No there will be additional charge for getting your license plate changed
In Arizona if your vehicle is repossessed and your get the vehicle back is it illegal for the repossession agent to charge a fee before they will return your licence plate?
In the State of Arizona, the license plate belongs to the debtor. They cannot charge you for your plate but they can charge you for inventory and storage of your personal property (which, incidently, includes your plate).
Area of plate?
The plates a parallel-plate capacitor are 2.50 mm apart and each carries a charge of magnitude 80.0 nC. The plates are in a vacuum. The electric field between the plates has magnitude of 4.00x106 V/m.
What is the electrical charge on the plate that causes the beam to bend toward that plate?
The electrical charge on the plate that causes the beam to bend toward it is negative. This negative charge creates an electric field that interacts with the positively charged ions in the beam, causing them to be attracted towards the negatively charged plate.
Does tectonic plate size effect earthquake magnitude?
Tectonic plate size does affect earthquake magnitude. Earthquakes happen when one plate slides above/below another plate, to do this it takes massive amounts of convection energy from the mantle to move the plate above. The larger the mass of the plate, the more energy is needed to move it which means that large plates have a lot of stored up energy in them before the quake in question. When the energy is released the plate boundary snaps releasing all the built up energy. As there was so much energy stored in the plate the more is released, causing a larger, more devastating earthquake.
Does a foam plate have a positive charge or a negative charge?
A foam plate typically does not have a significant overall charge. However, it can acquire a temporary charge due to friction or contact with other charged objects, resulting in either a positive or negative charge depending on the circumstances.
What plates caused the recent Japanese earthquake?
The Indo-Australia plate subducted (slipped) underneath the Sunda Plate (A small plate trapped between the Eurasian and the Indo-Australian plates), displacing 1,600Km of plate boundary 15m vertically. This causes an underwater earthquake with magnitude 9.1 on the MMS (Moment Magnitude Scale). This caused 3 waves to be formed. Some of which travelled at 500mph.
Did the largest magnitude earthquake in the past year occur at a subduction zone plate boundary?
Yes. All known earthquakes of magnitude 9.0 or greater have occurred at subduction boundaries.
How can you charge a metallic plate?
a metalic sheet can be charge by induction and conduction to keep it on insulated stand
A circular plate with radius 1.61 m contains 793 μC of a charge uniformly distributed. Find the magnitude of the electric field near the plate.?
To find the electric field near the charged plate, you can use the formula for electric field due to a charged disk: ( E = \frac{\sigma}{2\epsilon_0}(1 - \frac{z}{\sqrt{z^2 + r^2}}) ), where ( \sigma ) is the charge density, ( \epsilon_0 ) is the permittivity of free space, ( z ) is the distance from the center of the disk and ( r ) is the radius. Substituting the values given, you can find the electric field magnitude near the plate.
