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What is the effect in output for changing input frequency in halfwave rectifier?
if filtered and loaded the average DC voltage will increase and the ripple AC voltage will decrease, but the peak voltage is unchanged. this is because the filter capacitor has less time to discharge into the load.if unfiltered or unloaded the voltage cannot change. unfiltered the waveform just follows the half cycle of the input. if filtered but unloaded the output is DC at the peak voltage of the input AC.
What is the use of a transformer in a rectifier?
Generally, the rectified voltage (DC Voltage) is less than the supply voltage (230 VAC or 110 VAC). Therefore, there is a need to step down the mains voltage to the required value before rectification. AC Voltage is denoted by the Root Mean Square (RMS) value which is equal to the peak voltage of the sine wave divided by 1.4 (square root of 2). Therefore, the out put of a full wave rectifier with a smoothening filter (say, a condenser) will be about 1.4 times the RMS value of AC Voltage. For eg. if we need 12 VDC output from the rectifier, the AC Voltage output of the transformer (which will be the input to the rectifier) should be 12/1.4 ie. 8.6 V. However, since a stabilized DC power supply will usually have some kind of a voltage stabilizer, the output of the rectifier can be higher. Therefore, the transformer output can be 12 volts RMS in this case. The DC output will be roughly 12 x 1.4 = 16.8 V and the stabilized DC voltage can be maintained at 12 V DC irrespective of small fluctuations in the AC mains voltage.
Why the bridge rectifier is best?
What is the advantage of using the bridge rectifier A: NONE no advantage the only advantage can be considered it the fact it will provide more voltage but never more power actually less by a .7 volt diode drop
Why input current of USis less than Output current?
Why input current of USis less than Output current?
How can a capacitor reduce the effects of ripple voltage?
The smoothing capacitor converts the full-wave rippled output of the rectifier (which is left over AC signal) into a smooth DC output voltage A smoothing capacitor after either a half-wave or full-wave rectifier will be charged up to the peak of the rectified a.c. Between peaks of the a.c. the stored voltage will drop by a degree dependent on how much current is drawn from it by the load. The larger the value of the capacitor, the less drop there will be, and therefore less ripple when loaded.
Output voltage of half wave rectifier without capacitor filter is less or more than rectifier with capacitor filter?
less
What is the effect in output for changing input frequency in halfwave rectifier?
if filtered and loaded the average DC voltage will increase and the ripple AC voltage will decrease, but the peak voltage is unchanged. this is because the filter capacitor has less time to discharge into the load.if unfiltered or unloaded the voltage cannot change. unfiltered the waveform just follows the half cycle of the input. if filtered but unloaded the output is DC at the peak voltage of the input AC.
The dc output voltage of the filtered rectifier is less than it should be What could be the problem?
Depends on what you think it should be doesn't it?
What is the Name of the transformer in which the output AC voltage is less than the input AC voltage?
It is a step-down transformer.
What is the use of a transformer in a rectifier?
Generally, the rectified voltage (DC Voltage) is less than the supply voltage (230 VAC or 110 VAC). Therefore, there is a need to step down the mains voltage to the required value before rectification. AC Voltage is denoted by the Root Mean Square (RMS) value which is equal to the peak voltage of the sine wave divided by 1.4 (square root of 2). Therefore, the out put of a full wave rectifier with a smoothening filter (say, a condenser) will be about 1.4 times the RMS value of AC Voltage. For eg. if we need 12 VDC output from the rectifier, the AC Voltage output of the transformer (which will be the input to the rectifier) should be 12/1.4 ie. 8.6 V. However, since a stabilized DC power supply will usually have some kind of a voltage stabilizer, the output of the rectifier can be higher. Therefore, the transformer output can be 12 volts RMS in this case. The DC output will be roughly 12 x 1.4 = 16.8 V and the stabilized DC voltage can be maintained at 12 V DC irrespective of small fluctuations in the AC mains voltage.
Why the bridge rectifier is best?
What is the advantage of using the bridge rectifier A: NONE no advantage the only advantage can be considered it the fact it will provide more voltage but never more power actually less by a .7 volt diode drop
How can you see that the transformer is a step down or a step up?
If the primary voltage (input) is less than the secondary (output) then it is a step-up. If the input is greater than the output then it is a step-down transformer.
Why common emitter configuration is mostly used for transistor as switch?
because in ce configuration value of input voltage requried to make the transistor on is very less value of the output voltage or output current
What are advantages of bridge rectifier?
A bridge rectifier will rectify both halves of a sine wave and give "continuous output" through 360 degrees of the input. Oh, and you don't need a center-tapped transformer to use it.
What are the advantages of half-wave rectifiers over full-wave rectifiers?
The full-wave rectifier conducts on every half cycle, whereas the half-wave rectifier conducts on every other half cycle.This halves the average current on each diode, halving the power dissipated by the diodes.It doubles the ripple frequency, making filtering easier.Since the ripple frequency is doubled, the peak-to-peak ripple voltage is approximately half, which means that less capacitance is required in the filter capacitor.Since the peak-to-peak ripple voltage is lower, the head-room between filtered and regulated voltage is less, meaning less power is dissipated by the regulator.Full wave rectifiers give a smaller output voltage ripple, resulting in a smoother output waveform. However, depending on the design, the output on a full wave rectifier may be slightly less (like around 0.4V less) than that of a half wave rectifier. This is normally due to the voltage drop increasing due to the presence of additional diodes in the circuit.
Why input current of USis less than Output current?
Why input current of USis less than Output current?
How do you reduce a ripple voltage?
You reduce ripple voltage by adding a low-pass filter. In the simplest case, you put a capacitor after the rectifier. The peak voltage will be the rectifier output voltage less the forward bias of the rectifier, while the minimum voltage will depend on current and capacitance. In a more complex case, you could use an LC filter, making the peak voltage smaller. Specifics are dependent on the power and performance requirements.
