You do not use AC to megger a device, because the purpose of meggering is to measure the insulation resistance of the device. You use DC to do that. If you used AC, you would be unable to differentiate between insulation leakage and capacitance.
You cant.
Many can measure both - Vrms (AC) or DC voltage.
because of the coupling between the two transister and absence of capacitance it can amplify both dc and ac
No, you cannot accurately measure the output voltage of an Automatic Voltage Regulator (AVR) using a DC meter, as the AVR typically regulates AC voltage for the generator. A DC meter is designed for measuring direct current voltage, while the voltage output from a generator is usually alternating current (AC). To measure the AC voltage effectively, you would need an AC voltmeter or a multimeter set to the AC voltage setting.
You do not use AC to megger a device, because the purpose of meggering is to measure the insulation resistance of the device. You use DC to do that. If you used AC, you would be unable to differentiate between insulation leakage and capacitance.
No. The ammeter must be designed to measure DC. Some clamp-on ammeters are designed to measure both AC and DC.
You cant.
Jae-Won George Hwang has written: 'Control of AC-DC-AC converters with minimized DC link capacitance under grid harmonic distortion'
Resistance Voltage (both AC and DC) Current (both AC and DC)
Many can measure both - Vrms (AC) or DC voltage.
A typical multimeter can measure: * AC & DC voltage (volt) * AC & DC current (amp) * resistance (ohm)
There are less loss occurs when we use DC supply than AC supply, because the frequency is zero in DC, so no Inductance & Capacitance exists.And there is no skin effect in the DC systems, so there is low resistance as compared to AC systems.Rac = 1.25*Rdcfrom Arun Kumar SRR
Typical VOMs can measure both AC and DC.
because of the coupling between the two transister and absence of capacitance it can amplify both dc and ac
Given that AB = 8 units and AD = 10 units, we can use the ratios of corresponding sides in similar triangles to find the measure of DC. Since triangle ADC is similar to triangle ABC, the ratio of DC to AB is equal to the ratio of AD to AC. Thus, DC/8 = 10/AC. Solving for DC, DC = 8 * 10 / AC.
as it acts ideally as open circuit for dc