A LED has a forward voltage drop dependent on it's composition. It is fairly constant within a small range of current flow. If the voltage is too high and the current is not limited, the LED will burn out. The brightness can be varied by varying the available current, but the voltage across the LED remains virtually the same.
This question is the wrong way round. Assuming you the light bulbs are identical, they are brighter when connected to the power source in parallel than in series. This is because each bulb uses the entire potential difference of the power source, whereas in series, the bulbs act as potential dividers, reducing the voltage across the others and therefore the current passing through all of them.
If it is brighter than it should be there is too much current and it will burn out early. This is usually caused by internal problems in the lightbulb, but could rarely be caused by excessive voltage in the circuit powering the lightbulb.
If two light bulbs are connected in the same series circuit, each one will glow dimmerthan it would if it were the only one in the circuit with the same power supply.
An electric light bulb, incandescant type, is designed to operate at a certain voltage. Let's take 12 volt car headlights for example. Two 12 volt lights are connected in parallel in a car to provide the headlights, the same 2 lights could be connected in series if used on a truck with a 24 volt battery, or 20 of the lights could be connected in series if connected to a 240volt home electric circuit. (In the US think of 10 connected in series on your 110 volt system.) The lights would each produce about the same light output, but the number of lights would cause more light in total. In series there is a problem, when one light failsm they all go out. That's why lights in a house are connected in parallel.
An LED will shine brighter as more current is pushed through it. There is a dimishing return on this - at some point, increasing current will not increase the brightness very much, and will cost significantly more in terms of power.
Usually a higher voltage will make a light bulb shine brighter; but if the voltage is too high, this can also destroy the light bulb.
I think you're thinking of Higher by Mere
Voltage on a light bulb is determined by the amount of electrical potential difference applied across its terminals. The higher the voltage, the brighter the bulb will shine. Light bulbs are typically rated to operate at a specific voltage, such as 120V for standard household bulbs.
The brightness of a light bulb is related to its power. In all electrical circuits, power is equal to Voltage*Current. Since the two bulbs are connected in series, they must have equal current. The voltage across any given element in a series circuit is proportional to its resistance, so whichever bulb has the higher resistance has a higher voltage and thus higher power and is brighter.
Oh, dude, let me break it down for you. If you connect a 40W bulb and a 60W bulb in series, the 60W bulb will glow brighter because it has a higher wattage rating. It's like having a race between a tortoise and a hare - the hare (60W bulb) is gonna shine brighter than the tortoise (40W bulb). So, yeah, the 60W bulb takes the spotlight in this series connection scenario.
Increasing the amount of electrical current flowing through the bulb's filament will make it shine brighter. Additionally, using a higher wattage bulb or a bulb with a higher lumen output will also produce a brighter light.
If the current is stronger then the bulb will be brighter.
yes
Tomorrow is going to be a BRIGHTER day. The sun is BRIGHTER today then yesterday. Some day I will shine BRIGHTER than the sun.
Wipe it with cloth I guess?
Adding more batteries increases the voltage supplied to the light, which results in more electrical energy being available for the light to emit. This increased energy allows the light to shine brighter as it consumes more power from the additional batteries.
Rub it with a peice of clothAnswerJust turn up the shine volume...you didn't know that?