In order to answer that, one would need to know what the circuit is designed to do (so
that he would know how to tell when the circuit is "working"), and would also need to
see the schematic diagram, in order to know exactly how the fixed resistor and the
thermistor are configured in the circuit, and what other components are involved.
Consider . . . If I came up to you on the street, or even for that matter in an Engineering lab,
and I said to you "I've got a circuit with a coil and a resistor in it. Will it work if the impedance
of the coil is greater than the resistance of the resistor ?", you would most certainly find
yourself at a loss, just as I do when I read your question.
In a series circuit, the total voltage supplied by the source is divided among the resistors based on their resistance values. According to Ohm's Law (V = IR), a resistor with a larger resistance will have a larger voltage drop when the same current flows through it. Therefore, the resistor with the highest resistance in a series circuit will indeed experience the largest voltage drop. This is because the voltage drop across each resistor is directly proportional to its resistance.
Ohms law is: V = I x R (voltage = current x resistance) ... therefore the larger the resistance the larger the voltage drop across that resistance.
Simply put, the purpose of a resistor is to 'resist' the flow of current. Ohm's Law tells us that for a given voltage, the larger the resistance, or value of that resistor, the lower the current that will flow. Ohm's Law states that I (current) = E (voltage) / R (resistance) - where current is measured in amps, voltage is measured in volts and resistance is measured in ohms.
In a series circuit, the voltage drop across each resistor is proportional to its resistance value according to Ohm's Law (V = IR). The total voltage supplied by the source is divided among the resistors, so the sum of the individual voltage drops equals the total voltage. As a result, resistors with higher resistance will have a larger voltage drop compared to those with lower resistance.
Greater value resistor will absorb more voltage than smaller value. The more voltage absorb with same value current flow, the larger body mass resistor will require. Body size depends on type of resistor (material resistor is made of).
In a series circuit, the total voltage supplied by the source is divided among the resistors based on their resistance values. According to Ohm's Law (V = IR), a resistor with a larger resistance will have a larger voltage drop when the same current flows through it. Therefore, the resistor with the highest resistance in a series circuit will indeed experience the largest voltage drop. This is because the voltage drop across each resistor is directly proportional to its resistance.
Short answer: yes. Most modern multimeters will not be damaged by external power when measuring resistance. But they will give erroneous readings. It is best to remove the power and disconnect the measured resistance from the larger circuit. A multimeter determines resistance by applying a small voltage, and measuring the resulting current. If the resistor has an external voltage source, then it will interfere with the measurement. Furthermore, if the resistance is connected to a larger circuit, then the resistance of this larger circuit will also be involved.
Ohms law is: V = I x R (voltage = current x resistance) ... therefore the larger the resistance the larger the voltage drop across that resistance.
The total resistance of a set of resistors in parallel is found by adding up the reciprocals of the resistance values, and then taking the reciprocal of the total. By removing a resistor the total current will lower. If you short out the parallel circuit as suggested it will take out the fuse that should be protecting the circuit.AnswerShorting-out a resistor in a parallel circuit, will act to short out the entire circuit, therefore, significantly increasing, not lowering, the current! And, as the previous answer indicates, this short-circuit current will operate any protective devices, such as a fuse.In a parallel circuit current does not lower but it will be increase if shorting-out one resistor in the two resistor parallel circuit, the circuit will become very low resistive and the larger current will flow through the short path.
Just as the name of the component implies, electrical current gets resisted and therefore it diminishes unless an equally, larger voltage difference in that section of the circuit is applied. V=IR Current is inversely proportional to Resistance (when one goes UP, the other goes DOWN) Voltage is directly proportional to Resistance
Simply put, the purpose of a resistor is to 'resist' the flow of current. Ohm's Law tells us that for a given voltage, the larger the resistance, or value of that resistor, the lower the current that will flow. Ohm's Law states that I (current) = E (voltage) / R (resistance) - where current is measured in amps, voltage is measured in volts and resistance is measured in ohms.
as we can deduce from its name, the resistor "resists" to the current (the movement of the electrons) so as the value of the resistor increases, the current flowing through it decreases. so when you use a smaller resistor, the current increases, however the tension between its poles decreases ( due to the voltage divider law). remember that the shortcircuit is due to the small value of the current , so we need always to have a resonable resistance on the circuit..... but not too high because joule losses we'll be more significant !! hope i've been clear :D
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In a series circuit, the voltage drop across each resistor is proportional to its resistance value according to Ohm's Law (V = IR). The total voltage supplied by the source is divided among the resistors, so the sum of the individual voltage drops equals the total voltage. As a result, resistors with higher resistance will have a larger voltage drop compared to those with lower resistance.
In a d.c. circuit, voltage drop is the product of resistance and current through that resistance.
A diode is an electronic component which only allows the current to pass through it in one direction. This is useful in many aplications, such as preventing current to flow in the wrong direction in a circuit. A resistor is also an electronic component, but instead of preventing the current from moving in a certain direction the resistor creates an electrical resistance which will effect the current passing through it. The larger the resistance of the resistor, which is measured in Ohm, the greater the effect it will have on the current.
A voltmeter is designed to operate like a very large resistor (order of megaOhms), in parallel to the circuit that it is measuring. As long as the voltmeter resistance is much larger than the circuit that it is measuring, it will draw very little current away from the circuit and will only minimally disturb the operating circuit. See related link. If the voltmeter is connected in series with the rest of the circuit, then that is the same as connecting a very large resistor in series.So for example if you have 10 volt battery and a 10 ohm resistor, that would be 1 amp (without the voltmeter). Now if the voltmeter is 10 megaohm, the total resistance is 10000010 ohms, so the current is 0.999999 microamperes, and the voltage across the 10 ohm resistor is 9.99999 microvolts, while the voltage across the voltmeter is 9.999990 Volts (these numbers are rounded, but you get the idea).Suppose you put in series with a 1 kiloOhm (not sure about that spelling) resistor. The total resistance is 10001000 ohms, and current is 0.99990 microamperes, the voltage across resistor is now 0.9999 millivolts (it was microvolts) and the voltage across the voltmeter is 9.9990001 volts