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What is meant by single array?
A single dimensional array, or one-dimensional array, is a contiguous block of memory that contains one or more elements, each of which can store a single fixed-width value. Since each element is the same length (in bytes), the total memory consumed by the array is equal to the product of the element length and the total number of elements.One-dimensional arrays can be thought of as being a single row or column of numbered pigeon holes (the elements), such that each hole may contain a single object (a value). The numbers identifying each element are a zero-based incremental subscript, or index number. Thus for an array of n elements, the indexes will be in the range 0 to n-1. Some languages permit the first index to be offset from 0 such that the indexes will be in the range offset to offset+n-1, however this does not alter the actual index which is always zero-based.Arrays permit random, constant-time access to any element in the array via the element's index. When accessing an element, the return value is a reference to the first memory address of that element. This is achieved through simple pointer arithmetic, such that element i will be found at memory address (i-1) x (size of element) bytes from the start address of the array (hence the index is always zero-based, regardless of any offset that is applied).The value's stored in the elements must be of the same intrinsic type, but can be variables or constants of any kind, including object references and pointer variables, even pointers to other arrays.Multi-dimensional arrays are merely an extension of one-dimensional arrays, such that each element contains a reference to another one-dimensional array (each element of which may refer to yet another one-dimensional array, and so on). For instance, a two-dimensional array can be thought of as being pigeon holes arranged in rows and columns, such that every row has the same number of columns, and every column has the same number of rows. A three-dimensional array can be thought of as being a cuboid of pigeon holes. Although it's difficult to imagine a four-dimensional array in a three-dimensional space, the easiest way to think of it is as being a one-dimensional array where each element contains a three-dimensional array. More simply, a series of cuboids arranged in a row or a column.Multi-dimensional arrays needn't reside in contiguous memory, however each individual one-dimensional array that makes up a multi-dimensional array must itself reside in contiguous memory.Accessing the individual elements of a multi-dimensional array requires one subscript per dimension. Thus for a cuboid that has 3 rows, 3 columns and 3 tiers, the middle box will be found at zero-based index (1, 1, 1). Again, simple pointer arithmetic is employed to determine the address of the element offset from the starting address of each one-dimensional array.
What is the time complexity of accessing an element of an N dimensional array?
n
An algorithm of deleting linked list?
To delete a linked list walk through the list and delete the memory allocated to each element, remembering the next element address, and then iterating or recursing the process using the next element address, until the next element address is null.
How are elements of an array stored in memory?
Computer memory is linear so a one dimensional array can be mapped on to the memory cells in rather straight forward manner.To find the actual address of an element one needs to subtract one from the position of the desired entry and then add the result to the address of the the first cell in the sequence.Having said that therefore it is necessary to know the starting address of the space allocated to the array and the size of the each element, which is same for all the elements of an array.The the location of the Ith element would be B+I*S where B is the base address(Starting address of the array) and S is the size of each element of the array.
Find out the address of the element A452 where A is a 3-dimensional array with subscript limits 1 you 6 1 j 7 and 0 k 4 when A is in row major addressing Assume base address is 1000 and word size is 2?
1. Find out the address of the element A(4,5,2) where A is a 3-dimensional array with subscript limits 1≤ i ≤6, 1≤ j ≤7 and 0≤ k ≤4 when A is in row major addressing. Assume base address is 1000 and word size is 2.Answer:Array(depth,col,row) means A(4,5,2)Address= BASE+ ((depthindex*col_size+colindex) * row_size + rowindex) * Element_SizeADDRESS=1000+((4*7+5)*5+2)*2(1000+((33*5)+2)*2(1000+(167*2))(1000+334)1334
What is the formula for calculating the volume of a solid using the area element in cylindrical coordinates?
The formula for calculating the volume of a solid using the area element in cylindrical coordinates is V r dz dr d.
What is meant by single array?
A single dimensional array, or one-dimensional array, is a contiguous block of memory that contains one or more elements, each of which can store a single fixed-width value. Since each element is the same length (in bytes), the total memory consumed by the array is equal to the product of the element length and the total number of elements.One-dimensional arrays can be thought of as being a single row or column of numbered pigeon holes (the elements), such that each hole may contain a single object (a value). The numbers identifying each element are a zero-based incremental subscript, or index number. Thus for an array of n elements, the indexes will be in the range 0 to n-1. Some languages permit the first index to be offset from 0 such that the indexes will be in the range offset to offset+n-1, however this does not alter the actual index which is always zero-based.Arrays permit random, constant-time access to any element in the array via the element's index. When accessing an element, the return value is a reference to the first memory address of that element. This is achieved through simple pointer arithmetic, such that element i will be found at memory address (i-1) x (size of element) bytes from the start address of the array (hence the index is always zero-based, regardless of any offset that is applied).The value's stored in the elements must be of the same intrinsic type, but can be variables or constants of any kind, including object references and pointer variables, even pointers to other arrays.Multi-dimensional arrays are merely an extension of one-dimensional arrays, such that each element contains a reference to another one-dimensional array (each element of which may refer to yet another one-dimensional array, and so on). For instance, a two-dimensional array can be thought of as being pigeon holes arranged in rows and columns, such that every row has the same number of columns, and every column has the same number of rows. A three-dimensional array can be thought of as being a cuboid of pigeon holes. Although it's difficult to imagine a four-dimensional array in a three-dimensional space, the easiest way to think of it is as being a one-dimensional array where each element contains a three-dimensional array. More simply, a series of cuboids arranged in a row or a column.Multi-dimensional arrays needn't reside in contiguous memory, however each individual one-dimensional array that makes up a multi-dimensional array must itself reside in contiguous memory.Accessing the individual elements of a multi-dimensional array requires one subscript per dimension. Thus for a cuboid that has 3 rows, 3 columns and 3 tiers, the middle box will be found at zero-based index (1, 1, 1). Again, simple pointer arithmetic is employed to determine the address of the element offset from the starting address of each one-dimensional array.
What is the time complexity of accessing an element of an N dimensional array?
n
How are three-dimensional arrays represented in memory Explain how address of an element is calculated in three dimensional array?
3-D arrays can be represented as a single dimension of tables. Each table has rows and columns. Each table may also refered as Page. Let a[x][y][z] is an element of a three dimensional array 'a' at the xth Page, Within that page yth row and zth column. In memory it will be stored as sequence of memory locations. Suppose array index starts from 0,0,0. If the first element of the array is stored in location M, The address of the a[i][j][k] = (i-1)U2U3 + (j-1)U3 + (k-1), Where U2 and U3 are the dimention of a table.
What is the memory address of some element if the base address is x and each element of the array takes e memory locations?
The memory address of some element if the base address is x, each element of the array takes e memory locations, and the index based zero of the element is i, is x + ie.
How do you disable a span element?
To disable a span element, the command disable () has to be used. The command disable () stores the address of the element as the node of the parent address.
How is the atomic mass of an element determined?
The atomic mass of an element is determined by calculating the weighted average of the masses of its isotopes, taking into account their relative abundance.
Which formula you will to calculate The memory address of fifth element of an array?
Awais khanLOC(LA[K]) =base(LA)+w(k-lowerbound)
Why does array index begins with 0 not with 1?
It is because array name implies its address and if you want to access first element of it pointer address logic is as below: Arrays first element address = array base address + 0 Arrays second element address = array base address + 1
Why is a weighted average required for calculating atomic mass?
Isotopes - that same element with a different atomic weight.
An algorithm of deleting linked list?
To delete a linked list walk through the list and delete the memory allocated to each element, remembering the next element address, and then iterating or recursing the process using the next element address, until the next element address is null.
How are elements of an array stored in memory?
Computer memory is linear so a one dimensional array can be mapped on to the memory cells in rather straight forward manner.To find the actual address of an element one needs to subtract one from the position of the desired entry and then add the result to the address of the the first cell in the sequence.Having said that therefore it is necessary to know the starting address of the space allocated to the array and the size of the each element, which is same for all the elements of an array.The the location of the Ith element would be B+I*S where B is the base address(Starting address of the array) and S is the size of each element of the array.
