Write a 'c' program to calculate the frequencies of different alphabets present in a given string the string of alphabets is to be taken as input from the keyboard?

Answer 1

/* For a short string, like "abaz" a Hashmap like (a:2, b:1, z:1) will be shorter, than a whole alphabet*/

#include<stdio.h>

#include<conio.h>

main()

{

int count,i,j;

char str[50];

printf("Enter string : ");

gets(str);

for(i=0;i<=strlen(str)-1;i++)

{

count=1;

if(str[i]==' ')

continue;

for(j=i+1;j<=strlen(str)-1;j++)

{

if(str[i]==str[j])

{

str[j]=' ';

count++;

}

}

printf("%c : %d \n",str[i],count);

}

getch();

}

/*Answered by Ankush Monga

Doing DOEACC B level*/

Answer 2

Here is simple code in plain C:

# include<stdio.h>

#include<string.h>

void main()

{

char str[220];

char a[]="ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz";

int i,j,count;

printf("enter a string: ");

gets(str);

for(i=0;i<220;i++)

{

for(j=0;j<52;j++)

{

if(a[j]==str[i])

count++;

break;

}

}

printf("\nNo. of alphabets enteres in the string = %d",count);

}