#include<stdio.h> #include<conio.h> int i=1, count=0,n; clrscr(); printf("Enter Any Number"); scanf("%d", &n); while(i<n) if(n%i==0) { count++; i++; } if(count==2) printf("Given Number is Prime"); else printf("Given Number is not Prime"); getch(); }
Loop through some numbers - for example, 2 through 100 - and check each one whether it is a prime number (write a second loop to test whether it is divisible by any number between 2 and the number minus 1). If, in this second loop, you find a factor that is greater than 1 and less than the number, it is not a prime, and you can print it out.
Begin Read num for(i=2; i<num; i++) if(num%2==0) then print "the number is not a prime no."; else if print "the number is prime"; end if Stop
look man that would take alot >>> Ill give you the way =============================================================================== this answer i write it now on net ! i read about that befor in it uni where i study i will chick out the answer and re write it best wishes 2024
int number; int i=2; while (i<number) { if(number%i==0) { printf("Not a prime no."); break; } else printf("number entered is prime"); getch(); }
(defun prime (num) (if (< 2 num) (do ((dividend 2 (1 + dividend)) (chk-to (sqrt num))) ((equal (rem num dividend) 0)) (when (<= chk-to dividend) (return t))) t))
You can write out this algorithm. This will then be programmed into the device to make determining prime numbers easier.
Find a prime number, add 2 to the number. Check if the new number is prime. IE : 3 is prime. 3+2 =5. 5 is prime. (3,5) are twin primes.
First write a program to generate the prime number. After one prime number was generated, divide the big int number by the prime number. If the remainder is zero then quotient is the second prime number ( also it is important to check whether the quotient is prime number or not because sometimes you will get wrong answer). Repeat the process until you get the result.
shell script for check whether the given no is prime or not??echo "input any number:"read nono=`expr $no`i=`expr 2`while [ $i -lt $no ]doif [ `expr $no % $i` -eq 0];thenecho "$no is not a prime no.."break 2fii=`expr $i +1`doneif [ $i -eq $no ];thenecho "$no is a PRIME no..."fi
VBnet program to find the prime numbers between 100 to 200?
Write your own prime number program and find out.
Write a function that implements an algorithm that checks to see if a particular integer is prime (returning a boolean). Write a program that uses that function on each number from 1 to 100, and if true, displays that number.
By learning how to program on C+.
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Since there is an infinite set of prime numbers the answer would be infinity.
You can check each individual number, whether it is a prime number. For numbers below 100, it is enough to check whether they are divisible by 2, by 3, by 5, and by 7. If a number is divisible by none of these, it is a prime number.
Just write a loop that goes through "candidates" (for example, numbers from 2 to 100). To check whether each number is a prime number, write a second loop that checks whether it is divisible by all numbers from 2 up to the number itself. If the first factor you thus find is the number itself, then it is a prime number. For example, in Java:...for (i=2; i