Write a c program to display 1 4 9 16..100?

Answer 1

Answer:CODE:

#include

main(){

int i = 0;

int counter = 1;

while(i <= 100){

i = counter*counter;

counter++;

printf("The value of i is:%d\n", i);

}

exit(0);

}

END CODE

I think this should work and display the results in the terminal. I haven't tried it though, so it might not work.

Answer:#include

int main (void) { puts ("1 4 9 16..100"); retun 0; }

Answer 2

#include<stdio.h>

#include<conio.h>

void main()

{

int num[10],i,j,temp;

clrscr();

printf("\n Enter 10 values of an array.....\n");

for(i=0;i<10;i++)

scanf("%d",&num[i]);

printf("\n array before sort ....\n");

for(i=0;i<10;i++)

printf("%d\t",num[i]);

for(i=0;i<9;i++)

{

for(j=i+1;j<10;j++)

{

if(num[i]<num[j])

{

temp=num[i];

num[i]=num[j];

num[j]=temp;

}

}

}

printf("\n array after sort .........\n");

for(i=0;i<10;i++)

printf("%d\t",num[i]);

getch();

}

Answer 3

#include<iostream>

int main()

{

for(int i=1;i<=10;++i)

std::cout<<++i<<std::endl;

return(0);

}

Alternatively:

#include<iostream>

int main()

{

int i=0;

while(i<10)

std::cout<<++i<<std::endl;

return(0);

}

Alternatively:

#include<iostream>

int main()

{

int i=0;

do{

std::cout<<++i<<std::endl;

}while(i<10);

return(0);

}

Alternatively:

#include<iostream>

int main()

{

repeat:

int i=0;

std::cout<<++i<<std::endl;

if(i<10)

goto repeat;

return(0);

}

Answer 4

void main()

{

int i,num=1;

clrscr();

while(num<=100)

{ i=2; while(i<=num)

{ if(num%i==0)

break;

i++; }

if(i==num)

printf("\n%d is Prime",num);

num++;

}

getch();

}

Answer 5

There are many ways to write it. I give you a few example of it. You can follow which will easy for you.

=> Using for loop:

#include <stdio.h>

main(void)

{

int i;

for(i = 1; i <= 10; i++)

{

printf("%d ", i);

}

}

=> Using While loop:

#include <stdio.h>

main(void)

{

int i = 1;

while(i <= 10)

{

printf("%d ", i);

i++;

}

}

=> Using d0-while loop:

#include <stdio.h>

main(void)

{

int i = 1;

do

{

printf("%d ", i);

i++;

} while(i <= 10);

}

Answer 6

#include <iostream>

int main()

{

for( unsigned int i = 1; i < 11; ++i )

{

std::cout << i << std::endl;

}

}