// HI THIS IS MAYANK PATEL
/*C Program to find Maximum of 3 nos. using Nested if*/
#include<stdio.h>
#include<conio.h>
void main()
{
int a,b,c;
// clrscr();
printf("Enter three number\n\n");
scanf("d%d",&a,&b,&c);
if(a>b)
{
if(a>c)
{
printf("\n a is maximum");
}
else
{
printf("\n c is maximum");
}
}
else
{
if(b>c)
{
printf("\n b is maximum");
}
else
{
printf("\n c is maximum");
}
}
getch();
}
nested if Statement
The most simpliest way is to use a nested loop. However this runs in O(N*N) time. For small arrays, this should be sufficient.
Sure! Here's a Java program that will print all the nested loops between 1 to 500: public class NestedLoopExample { public static void main(String[] args) { for (int i = 1; i <= 500; i++) { for (int j = 1; j <= 500; j++) { System.out.println("i=" + i + ", j=" + j); } } } } This program uses two nested for loops to iterate from 1 to 500. It prints the value of i and j for each iteration of the loops.
You use a nested if when the condition is dependent upon another condition. For example: if (ptr != nullptr) { // ptr is non-null -- test the value it refers to if (ptr* == 0) { // the value pointed to by ptr is zero } else { // the value pointed to by ptr is non-zero } } In this case, the alternative to a nested if creates an inefficiency: if (ptr != nullptr && *ptr == 0 ) { // ptr is valid and refers to the value zero } else if (ptr != nullptr) { // ptr is valid and refers to a non-zero value } In this example, the expression "ptr != nullptr" is evaluated twice when ptr is valid and refers to a non-zero value. The nested if only evaluates this expression one time.
C++ if() statements implements a comparison and a jump opcode. By way of example, consider the following code:if( x 100 ) generates a compare and jump opcode (cmp and jne).The cmp opcode compares the value of x with 64h (100 decimal) which will either set or clear ZF (the zero flag). If x is 100, then ZF will be unset, otherwise it will be set.The jne (jump if not equal) opcode tests ZF. If it is set, then x was not 100 and the operand (1181934h) is passed to the PC register (the program counter). The IR (instruction register) will fetch the value from PC on the next cycle. This ultimately causes execution to jump to the statement immediately following the else clause of the if statement (the second printf statement).If ZF is not set, then x really was 100 and the PC register remains unaffected. At that point the PC register will contain the value 0118191Bh, which is the next instruction after the if statement, thus execution simply falls through to the first printf statement. After processing the printfinstructions, execution will reach the else clause which simply forces a jump to bypass the second printfstatement.Thus, one of the printf statements is executed and then execution continues from the instruction at 118194Bh, which is not shown but is the next instruction after the second printfstatement.
nested if Statement
You really need some nested loops; but some programming languages might allow you to write this as one statement.
we use "nested if" if we have to test a large number of possibilities and trials i an if statement.
If(condition) { if-else statement; } else { if-else statement; }
yes,we can
What you are asking would be not be a nested if then else statement, in pseudocode what you are asking would be:if condition thendo thiselsedo that[this is pseudo code because the 'and' would be rendered differently in other languages and there potentially would be statement terminators, etc]A nested if statement would be:if condition1 thenif condition2 thendo thiselsedo thiselsedo thatThe second if statement is nested within the first one, clearly the nesting can go on quite deeply.
In C a structure within a structure is called nested. For example, you can embed a while loop in another while loop or for loop in a for loop or an if statement in another if statement.
The most simpliest way is to use a nested loop. However this runs in O(N*N) time. For small arrays, this should be sufficient.
Sure! Here's a Java program that will print all the nested loops between 1 to 500: public class NestedLoopExample { public static void main(String[] args) { for (int i = 1; i <= 500; i++) { for (int j = 1; j <= 500; j++) { System.out.println("i=" + i + ", j=" + j); } } } } This program uses two nested for loops to iterate from 1 to 500. It prints the value of i and j for each iteration of the loops.
An example of a question that includes the keyword "negating nested quantifiers" could be: "Explain how to negate the statement 'For every x, there exists a y such that P(x, y)' in terms of nested quantifiers."
You use a nested if when the condition is dependent upon another condition. For example: if (ptr != nullptr) { // ptr is non-null -- test the value it refers to if (ptr* == 0) { // the value pointed to by ptr is zero } else { // the value pointed to by ptr is non-zero } } In this case, the alternative to a nested if creates an inefficiency: if (ptr != nullptr && *ptr == 0 ) { // ptr is valid and refers to the value zero } else if (ptr != nullptr) { // ptr is valid and refers to a non-zero value } In this example, the expression "ptr != nullptr" is evaluated twice when ptr is valid and refers to a non-zero value. The nested if only evaluates this expression one time.
In order to achieve multiple decisions in a program, you have to join multiple IF statements and use the AND logic to determine if they are true of false, whereas in a nested decision, only one statement must be true in order for it to move forward or End. If (applicant >= 21) AND (applicant <= 19) then add 1 to hireList Else add 0 to hireList End if IF condition1 THEN IF condition2 THEN ASP Statement(s) for when condition2 is met ELSE ASP Statement(s) when this condition2 is NOT met END IF END IF