Write a c programme to find sum of individual digits of a given positive integers?

Answer 1

int sumDigits(int n) {
int sum = 0;

while( n > 0 ) {
sum += (n % 10); // add last digit of n to sum
n /= 10; // divide n by 10 to "chop off" the last digit

}

return sum;

}

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C program to find the sum of entered digit: By Jatinder Pal Singh

#include
#include
void main()
{
clrscr();
int n,num,x,sum=0;
printf("Enter a number=");
scanf("%d",&n);
while(n>0)
{
x=n%10;
sum=sum+x;
n=n/10;
}
printf("Sum of digits of a number=%d",sum);
getch();
}

Answer 2

#include
#include

using std::cin;
using std::cout;
using std::endl;
using std::string

int main()
{
const int numberOfdigits = 6;
string myNumber = "0";
char myNumberChar[numberOfdigits] = {0};
cout << endl << "Enter 5 digit integer: ";
cin >> myNumber;

int sumOfDigits = 0;
int temp = 0;
for (int arrayIndex = 0; arrayIndex < (numberOfdigits - 1); arrayIndex++)
{
temp = atoi(&myNumber.substr(arrayIndex, 1)[0]);
sumOfDigits += temp;
}
cout << endl << "Sum of 5 digits is: " << sumOfDigits << endl;

system("PAUSE");
return 0;

}

Answer 3

#include

int main()
{
int num, dig, sum = 0; /* be sure to initialize sum to 0 */

printf("Enter number:");
scanf("%d", &num); /* num is our actual number */

while (num > 0) /* While we still have digits in num */
{
dig = num % 10; /* Get the rightmost digit in num... */
sum += dig; /* and add it to sum */
num = num / 10; /* Get rid of the rightmost digit in num */
}

printf("Result: %d", sum);
return 0;
}

Answer 4

#include

#include

void main()

{

int sumdig(int);

int n,sum,d,f,rev=0;

clrscr();

printf("enter the number");

scanf("%d",&n);

sum=sumdig(n);

printf("%d",sum);

getch();

}

int sumdig(int n)

{

int sum,d,r=0;

if(n==0)

return(0);

else

sum=n%10+sumdig(n/10);

while(sum!=0)

{

d=sum%10;

r=r+d;

sum=sum/10;

}

return(r);

}

Answer 5

To determine the value of the least-significant digit in a number, you divide by the base and take the remainder. To get the next digit, divide by the base and repeat. The following function will sum the digits of any integer (the length does not matter):

int sum_digits (int num, int base=10) { // assume decimal notation by default

int sum = 0;

while (num) {

sum += num%base; // add the least-significant digit

num /= base; // move all digits one place to the right

}

return sum;

}

Answer 6

I am writing only the function

int sum_of_digit(int num)
{
int sum=0;
while(num)
{
sum=sum+num%10;
num=num/10;
}
return sum;
}