Here's a simple Java program that uses a for loop to generate the first 10 multiples of the first 10 natural numbers:
public class Multiples {
public static void main(String[] args) {
for (int i = 1; i <= 10; i++) {
System.out.print("Multiples of " + i + ": ");
for (int j = 1; j <= 10; j++) {
System.out.print(i * j + " ");
}
System.out.println();
}
}
}
This program iterates through the first 10 natural numbers and prints their multiples from 1 to 10.
#include<stdio.h> main(void) { int n; int i; printf("Type n: "); scanf("%d",&n); for(i=1;i<=n;i++) //generates natural numbers from 1,....,n. printf("%d\n",i); //prints these numbers to standard output }
which r the first 10 amstrong numbers??
Write an. Algorthim. To. Find the. Sum. Of. First15 natural. Numbers
#include<stdio.h> int main () { int odd=1; int count=0; while (count++<10) { printf (%d\n", odd); odd+=2; } return 0; }
For the first 5 natural numbers (integers):x = 1 + 2 + 3 + 4 + 5print xFor 'n' amount of natural numbers (Python v2 example)n = int(raw_input('Enter max integer: '))count = 0sumn = 0while count < n:sumn = sumn + 1count = count + 1print sumn
That isn't true.
1,2,
Multiples are the numbers that can be divided by their factors. Like multiples of 2 are 2,4,6,8,10 and so on .The numbers obtained from the multiplication of 2 with all the natural numbers are the multiples of 2.
No. Odd numbers can be written as the sum of consecutive integers, but some multiples of odd numbers are even.
Every number has 1 as a factor.
there are an infinite number of these. Take each natural number, remembering that these are the numbers, 1,2,3,4,5... and multiply it by 340 and those are the multiples.
Yes. The entire set of natural numbers is closed under addition (but not subtraction). So are the even numbers (but not the odd numbers), the multiples of 3, of 4, etc.
Well, honey, I hate to break it to you, but the numbers 8 and 36 are not multiples of 5. Natural numbers are those positive integers starting from 1, and multiples of 5 are numbers that can be divided by 5 without any remainder. So, in this case, you're barking up the wrong tree.
Complex numbers, Real numbers, Rational numbers, Integers, Natural Numbers, Multiples of an integer.
All numbers have an infinite amount of multiples.
Consider the number pair (1, n), where n is an integer. Their LCM is n. By selecting different values of n, these sets can generate all integers as their LCMs. Therefore, the list of LCMs is the list of all Natural numbers.
The infinite set of numbers which are multiples of three. The infinite set of numbers which are multiples of three. The infinite set of numbers which are multiples of three. The infinite set of numbers which are multiples of three.