Write a program in c language that inputs 2 number and solve using euclidean algorithm?

Answer 1

#include<stdio.h>

#include<conio.h>

void main()

{

int a,b,max,min,r;

printf("Enter the values of a,b");

scanf("%d%d",&a,&b);

if(a>b)

{

max=a;

min=b;

}

else

{

max=b;

min=a;

}

while((max%min)!=0)

{

r=max%min;

if(r==0)

{

break;

}

max=min;

min=r;

}

printf("GCD=%d",min);

getch();

}

Answer 2

#include< stdio.h>

#include< conio.h>

void main()

{

int a,b,c;

cout< < "Enter two nos : ;

cin>>a>>b;

c=a*b;

while(a!=b)

{

if(a>b)

a=a-b;

else

b=b-a;

}

cout< < "HCM \t= " < < a;

cout< < "LCM \t= " < < c/a;

getch();

}

Answer 3

#include

#include

int main(void) {

using namespace std;

double a {}, b {}; // zero-initialised

while (true) {

cout<<"Input two non-zero numbers: ";

stringstream ss {};

cin>>ss;

if (ss>>a && ss>>b && a && b) break; // input parsed correctly!

cout<<"Error: numbers not recognised!\n!";

}

cout<<"Sum = "<

cout<<"Difference = "<

cout<<"Product = "<

cout<<"Quotient= "<

}

Note that the while loop handles all input errors. The input and output streams both operate on character sequences, so placing the current input into a localised stringstream is by far the safest and easiest way to accept all input without corrupting the input stream. If the conversion to double should fail for any reason, no harm is done as the stringstream will be recreated anew on the next iteration.

Example output:

Input two non-zero numbers: 6 3

Sum = 9.0

Difference = 3.0

Product = 18.0

Quotient = 2.0

Answer 4

how to write a programm to add number like123 in c language