Write a program to accept a character value from the user and sHow is its ASCII value?

Answer 1

You don't need to write a program to do this. Each character (char) is actually an int. If you want to see the ASCII value of a char you can simply:

char c = 'a';

System.out.print( (int)c );

Answer 2

import java.io.BufferedReader;

class GetAsciiValue

{

public static void main(String arg[])

{

InputStreamReader isr=new InputStreamReader(System.in);

BufferedReader br= new BufferedReader(isr);

System.out.println("Enter a character or string");

String s=br.readLine();

for(int i=0;i<s.length();i++)

System.out.println("ASCII value of:"+s.charAt(i)+"is"+(int)s.charAt(i));

}

}

Answer 3

#include

#include

main()

{

clrscr();

int x;

char y;

printf("enter the number");

scanf("%d",&x);

printf("enter the char");

scanf("%c",&y);

if(sizeof(x)==2))

{

printf("the equivalent char for given integer is %c ",x);

}

elseif(sizeof(y)==1)

printf("the equivalent integer for given char is %d ",y); getch();

}

Answer 4

#include<stdio.h>

#include<conio.h>

void main()

{

char ch;

clrscr();

printf("Enter the character\n");

scanf("%c",&ch);

printf("The ASCII value of entered character is : %d",ch);

getch();

}

Answer 5

class ASCII

{

public void main(){

char a;

for (int i = 65; i <=90; i++)

{

a = (char)i;

System.out.println(i + ": " + a); // TODO add your handling code here:" +

}

}

}

Answer 6

ASCII value of 'a' is 97. Here is the complete list of ASCII value of characters in C Programming. When a character is stored in variable of type.