char x,y,z;
x=100;
y=200;
z=x+y; /* overflow */
x=100;
y=100;
z=x+y; /* overflow if signed, okay if unsigned */
x=100;
y=20;
z=x+y; /* okay */
"Mean" usually means "average", so you just add the numbers together, then divide by 8.
Da program pa yakho obo olambawa
#include<iostream.h> #include<conio.h> void main() { int a, b, c; clrscr(); cout<<"enter the two numbers"; cin>>a; cin>b; c=a+b; cout<<"Addition of two numbers="<<c; getch(); }
#include int main(void){int a;for(a=100;a
You can make use of pointers to achieve this.void add( int *a, int *b){(*a) += (*b);}Now if two numbers a and b are given and you need to store the value in variable c, then you would perform:c = a;add(&c,&b);
write it in 8085
int main() { int num1; int num2; int result = num1 + num2; return 0; }
"Mean" usually means "average", so you just add the numbers together, then divide by 8.
Mov a.#000ff, mov b,#0008f add a,b
Add the numbers into one variable as you read them in. But if you prefer, you can read the numbers into an array and then use a loop to add the numbers together.
yes ,i can add the website link in java program when we write.
A+(B+C**3) (A-(+D+B/A+B)
1. Write the program 2. Compile and link it 3. Execute it by entering its name at command prompt
USING STRING LITERAL VALUES TO ADD 2 NUMBERS If you just want to show the outcome of two numbers you have: PRINT 4 + 5 This will print '9' the answer to 4 + 5. If you want to show the addition: PRINT "4 + 5 = "; 4 + 5 This will show the question and then calculate the answer. If you want the user to input numbers to add, use variables and then add them the same way. ====== COLLECTING USER INPUT FROM THE KEYBOARD/USING NUMERIC VARIABLES In the following example, the end user can get to interact with the program by typing in their numbers at the keyboard; then, pressing the [Enter] key. CLS PRINT "PROGRAM: Add 2 numbers" PRINT INPUT "Enter the 1st number: ", number1 INPUT "Enter the 2nd number: ", number2 PRINT sumTotal=number1+number2 PRINT "The sum total is: "; sumTotal PRINT INPUT "Again, Y/N"; yesNo$ IF UCASE$(LEFT$(yesNo$,1))="Y" THEN RUN END ====== CREATE FUNCTION/THEN, MAKE A FUNCTION CALL TO ADD 2 NUMBERS Another way to write this program is to create a function/then, make a function call... '*** PROGRAM: Add 2 numbers... '*** Variable declaration list... number1=7 '...initialise numeric variable 1 number2=3 '...initialise numeric variable 2 '*** Main program... CLS '...(CL)ear the (S)creen PRINT add(number1,number2) '...make function call/passing in 2 numbers to add END '...END of program/halt program code execution '*** Function(s)... FUNCTION add(num1,num2) '...this line marks the start of the Function add=num1+num2 '...this line returns the sum total of the 2 numbers END FUNCTION '...this line marks the end of the Function
Da program pa yakho obo olambawa
GOUDHMARINI
#include<iostream.h> #include<conio.h> void main() { int a, b, c; clrscr(); cout<<"enter the two numbers"; cin>>a; cin>b; c=a+b; cout<<"Addition of two numbers="<<c; getch(); }