Write a program to find the average of three numbers?

Answer 1

#incude<iostream.h>

#include<conio.h>

void main()

{

clrscr();

int a,b,c,d,avg;

cout<<"enter s numbers";

cin>>a>>b>>c>>d;

d=a+b;

avg=d\3;

cout<<"the average is"<<s;

getch();

}

Answer 2

You have not clarified in which language are you looking to program.

If you are coding in C language then program would be something like this.

#include<stdio.h>

#include<conio.h>

void main()

{

int a,b,c; //Declare Integers

float avrg; //Declaring Average

printf("enter the first number:"); //Asks for first no

scanf("%d",&a); //You put in first no

printf("enter the second number:"); //Enter 2nd No

scanf("%d",&b); // You put in 2nd No

printf("enter the third number:"); //Enter Third No

scanf("%d",&c); //You enter third no

avrg=(a+b+c)/3.0; //It calculates the average by formula of average

printf("The average of given numbers is: ",avrg); //It finally prints average

getch();

}

If you are programming in C++ , program would be something like this.

//Include Libraries

#include

#include

void main (Void )

{

//Declare Variables

int a,b,c;

float avg;

//You are asked to put no's and you put them

cout<<"Enter first No"<

cin>>a;

cout<<"Enter Second No"<

cin>>b;

cout<<"Enter Third No"<

cin>>c;

//Finally Average is calculated

avg = (a+b+c)/3.0

//Average is printed finally.

cout<<"Average of these no's is"<

}

Answer 3

int average(int n, ...)

{

int sum = 0;

va_list arg_list;

va_start(arg_list, n);

for(int i = 0; i < n; i++)

sum += va_arg(arg_list, int);

va_end(arg_list);

return(sum / n);

}

Answer 4

auto 100

0100 // Name

0110 // Date

0120 // to display the sum of three numbers

0130 INPUT "please enter the first number":number1

0140 INPUT "Please enter the second number":number2

0150 INPUT "Please enter the third number":number3

0160 total=number1+number2+number3

0170 END

run

(the next bit should come up)

please enter number1(enter)

please enter number2(enter)

please enter number3(enter)

total is (total of all three)

Answer 5

#include<iostream>

int main()

{

double nums[3] {};

double sum {};

for (size_t loop=0; loop!=3; ++loop)

{

std::cout << "Enter number #" << loop+1 << std::endl;

while (true)

{

std::cout << "Enter a floating point value: ";

if (std::cin >> nums[loop])

break;

std::cerr << "Bad input!" << std::endl;

}

sum += nums[loop];

}

std::cout << "Sum of numbers: " << sum << std::endl;

std::cout << "Average: " << sum/3 << std::endl;

}

Answer 6

You do not need a program Total the nubers and divide by 5.

an example:

225+455+340+600+380=2000; 2000/5=400

Answer 7

6, 8 and 7