Write a program to read any five numbers and print average value?

Answer 1

#include<stdio.h>

#include<conio.h>

#define p printf

#define s scanf

int main()

{

clrscr();

int a,b,c,d,e;

int ans;

p("\nEnter first no.:");

s("%d",&a);

p("\nEnter second no.:");

s("%d",&b);

p("\nEnter third no.:");

s("%d",&c);

p("\nEnter fourth no.:");

s("%d",&d);

p("\nEnter fifth no.:");

s("%d",&e);

ans=(a+b+c+d+e)/5;

p("\nThe average is: %d",ans);

getch();

return 0;

}

Answer 2

Here is a program capable of doing that:

#include <stdio.h>

#define MAX 5

int main() {

int ind, num, sum = 0;

for (ind = 0; ind < MAX; ind++) {

printf("Enter %d number: ", ind + 1);

scanf("%d", &num);

sum += num;

}

printf("Average of 5 numbers are %f\n", (float)sum / MAX);

return 0;

}

Answer 3

#include <iostream.h>

#include <conio.h>

void main()

{

float arr1[5], avg=0, sum=0;

cout<<"Enter 5 values for sum and average: "<<endl;

for(int i=0; i<5; i++)

{

cin>>arr1[i];

sum+=arr1[i];

}

avg=sum/5;

cout<<"Sum of 5 values is: "<<sum<<endl;

cout<<"Average of 5 values is: "<<avg;

getche();

}

Answer 4

Start a loop

Ask for the user for a value

Add the value to a running sum

At end of loop, divide the running sum by 5 (or the total number of numbers entered by the user).