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Write an algorithm and draw corresponding flow chart to check whether a given string is a palindrome or not?
Program
# include<stdio.h> void main() { long n,rev,t; int r; clrscr(); printf("Enter number : "); scanf("%ld",&n); t=n; rev=0; while(t>0) { r=t%10; rev=(rev*10)+r; t=t/10; } if(n==rev) printf("Number is palindrom"); else printf("Number is not palindrom"); getch(); }
algorithm
step 1 : input n
step 2 : s = 0, a=n
step 3 : while(n>0)
begin
rem=n%10
s=s*10+rem
n=n/10
end
step 4 : if(s==a)
print 'it is a palindrome'
else
print 'it is not a palindrome'
step 5 : stop
What else can I help you with?
Using Python write an algorithm that takes a string as input and determines whether or not it is a palindrome?
def isPalindrome(s): return s == s[::-1] then just call the function with a string like isPalindrome('poop')
Program to check that given string is palindrome or not in C?
/*To check whether a string is palindrome*/includeincludevoid main () { int i,j,f=0; char a[10]; clrscr (); gets(a); for (i=0;a[i]!='\0';i++) { } i--; for (j=0;a[j]!='\0';j++,i--) { if (a[i]!=a[j]) f=1; } if (f==0) printf("string is palindrome"); else printf("string is not palindrome"); getch (); }
Write a pseudo logic to check whether a string is palindrome or not?
Prepare the string for processing: Remove all punctuation from the string (e.g., commas, hyphens, whitespace, etc). Convert to the same case (e.g., lower-case). Instantiate two pointers, one pointing at the first character, the other pointing at the last character. Process: If the two pointers are pointing at the same position or have crossed each other, the string is a palindrome. Otherwise, compare the characters being pointed at. If they are not equal, the string is not a palindrome. Otherwise, move both pointers one position towards the middle of the string and repeat the process.
Bluej program-read a string and check if the given string is a palindrome?
import java.util.Scanner; public class Palindrome{ public static void main(String[] args){ String front; String back =""; char[] failure; String backwards; Scanner input=new Scanner(System.in); System.out.print("Enter a word: "); front=input.next(); front=front.replaceAll(" ", ""); failure=front.toCharArray(); for (int i=0; i<failure.length; i++){ back=failure[i] + back; } if (front.equals(back)){ System.out.print("That word is a palindrome"); }else System.out.print("That word is not a palindrome"); }}
What is pallendrome in java?
palindrome in every language means same. it means on reversing a number or string, if we get the same number or string as the case may be ,then the number or string is called palindrome. eg: 1221,111,252 or LIRIL,MADAM etc .
Using Python write an algorithm that takes a string as input and determines whether or not it is a palindrome?
def isPalindrome(s): return s == s[::-1] then just call the function with a string like isPalindrome('poop')
Write a PHP program to check whether the string is palindrome or not?
You can do this: <?php if ( $word === strrev( $word ) ) { echo "The word is a palindrome"; } else { echo "The word is not a palindrome"; }
Program to check that given string is palindrome or not in C?
/*To check whether a string is palindrome*/includeincludevoid main () { int i,j,f=0; char a[10]; clrscr (); gets(a); for (i=0;a[i]!='\0';i++) { } i--; for (j=0;a[j]!='\0';j++,i--) { if (a[i]!=a[j]) f=1; } if (f==0) printf("string is palindrome"); else printf("string is not palindrome"); getch (); }
How do you determine if a given string is palindrome or not?
Reverse the string and compare it to the original. If they match, then it is a palindrome.
Write an algorithm to check whether a given string is palindrome or not?
#include <stdio.h> #include <conio.h> #include <string.h> void input(char a[ ]) { int i; printf("\n enter string\n"); scanf("%s",a); } void output(char a[ ]) { printf("\n string is %s",a); } int palindrome(char a[ ]) { int n,i; n=count(a); n=n-1; i=0; for(;a[n]==a[i] && n>=i;i++,n--); if(n>=i) return 0; else return 1; } void main( ) { char a[80],b[80],s; int n; printf("\n check palindrome"); input(a); n=palindrome(a); output(a); if(n==1) printf("\n palindrome"); else printf("\n not palindrome"); getch(); }
Design a algorithm to check whether a given string is palindrome or not?
#include <stdio.h> #include <conio.h> #include <string.h> void input(char a[ ]) { int i; printf("\n enter string\n"); scanf("%s",a); } void output(char a[ ]) { printf("\n string is %s",a); } int palindrome(char a[ ]) { int n,i; n=count(a); n=n-1; i=0; for(;a[n]==a[i] && n>=i;i++,n--); if(n>=i) return 0; else return 1; } void main( ) { char a[80],b[80],s; int n; printf("\n check palindrome"); input(a); n=palindrome(a); output(a); if(n==1) printf("\n palindrome"); else printf("\n not palindrome"); getch(); }
Design an algorithm to check whether a given string is a palindrome or not?
#include <stdio.h> #include <conio.h> #include <string.h> void input(char a[ ]) { int i; printf("\n enter string\n"); scanf("%s",a); } void output(char a[ ]) { printf("\n string is %s",a); } int palindrome(char a[ ]) { int n,i; n=count(a); n=n-1; i=0; for(;a[n]==a[i] && n>=i;i++,n--); if(n>=i) return 0; else return 1; } void main( ) { char a[80],b[80],s; int n; printf("\n check palindrome"); input(a); n=palindrome(a); output(a); if(n==1) printf("\n palindrome"); else printf("\n not palindrome"); getch(); }
How do you write a program in C to check whether a word is a palindrome or not?
It is a simple program. i think u may understand it :#include#include#includevoid main(){char s[10]=answers.com;char x[10];int a;clrscr();strcpy(x,s);strrev(s);a=strcmp(s,x);if(a==0){printf("the entered string is palindrome");}else{printf("the entered string is not palindrome");}output:given string is not palindrome
What are examples of a palindrome program forward and backwards?
To check if a string is a palindrome, point to each end of the string and work inwards towards the middle. If the characters pointed at differ, the string is not a palindrome. When the pointers meet or cross each other, the string is a palindrome. Note that the string cannot contain whitespace or punctuation and comparisons must not be case-sensitive.
What are the explanation steps for palindrome program?
If you want to check whether a string is a palindrome, you can reverse the string (for example, the Java class StringBuffer has a reverse() method), and then compare whether the two strings - the original string and the reverted string - are equal. Alternately, you could write a loop that checks whether the first character of the string is equal to the last one, the second is equal to the second-last one, etc.; that is, you have a counter variable (in a "for" loop) that goes from zero to length - 1 (call it "i"), and compare character #i with character #(length-i-1) inside the loop.
Is there a way to use regex to determine if a given string is a palindrome?
Yes, you can use regex to determine if a given string is a palindrome by reversing the string and then comparing it to the original string using regex.
What is a string palindrome?
A string palindrome is some words that put together form a sentence. An example is "A man, a plan, a canal - Panama".
