Write an assembly language programin 8085 to find a square of a given number?

Answer 1

To find the area of a square, the person can simply multiply length times width, which would be two sides of the square. To find area of a circle, the person must use the equation ((pie)(r))(squared).

Answer 2

#include

using std::cin;

using std::cout;

using std::endl;

void getData(double& length, double& width);

double Area(double length, double width);

int main()

{

double length = 0.0;

double width = 0.0;

getData(length, width);

cout << endl << "Area is: " << Area(length, width) << endl;

system("PAUSE");

return 0;

}

void getData(double& length, double& width)

{

cout << endl << "Enter length: ";

cin >> length;

cout << "Enter width: ";

cin >> width;

}

double Area(double length, double width)

{

return (length * width);

}

*The program was checked in VS2008

Answer 3

Lxi d,0000h

lhld 4000h

mov c,l

mov b,h

up: dad d

dcx b

jnz up

hlt