Write c program to find multiplication of three numbers?

Answer 1

#include<stdio.h>

#include<conio.h>

void main()

{

int a,b,c;

int Result;

printf("enter the value of a:");

scanf("%d", &a);

printf("enter the value of b");

scanf("%d", &b);

printf("enter the value of c");

scanf("%d", &c);

Result=a*b*c;

printf("%d", Result);

getch();

}

Answer 2

Sure, darling. Here's a simple C program to find the multiplication of three numbers:

#include <stdio.h>

int main() {
    int num1, num2, num3;
    
    printf("Enter three numbers: ");
    scanf("%d %d %d", &num1, &num2, &num3);
    
    int result = num1 * num2 * num3;
    
    printf("The multiplication of the three numbers is: %d", result);
    
    return 0;
}

Run along now and give it a try!

Answer 3

Here is a simple C program to find the multiplication of three numbers:

#include <stdio.h>

int main() {
    int num1, num2, num3, result;
    
    printf("Enter three numbers: ");
    scanf("%d %d %d", &num1, &num2, &num3);
    
    result = num1 * num2 * num3;
    
    printf("Multiplication of the three numbers is: %d\n", result);
    
    return 0;
}

This program prompts the user to enter three numbers, multiplies them together, and then prints out the result.

Answer 4

Oh, dude, finding the multiplication of three numbers in C? That's like asking me to spell "banana." Anyway, here's a quick and dirty code for ya:

#include <stdio.h>

int main() {
    int num1 = 5, num2 = 7, num3 = 9;
    int result = num1 * num2 * num3;
    
    printf("The multiplication of %d, %d, and %d is: %d\n", num1, num2, num3, result);
    
    return 0;
}

There you go, a program that multiplies 5, 7, and 9. Enjoy!

Answer 5

#include

int main()

{

int a,b,c,d;

printf(“\n Enter three numbers to multiple”);

scanf(“%d,%d,%d”,&a,&b,&c);

d=abc;

printf(“\n Result=%d”,d);

return 0;

}

Answer 6

simply enter three nos. lyk a b and c and use the code a*b*c and print the result!!

Answer 7

Printf("/n enter three numbers to multiply");

Scanf("%d,%d,%d,"&b,&b,&c);d=abc

Printf("/nresult=%d,"d);

Return o;

}}