Write c program to make calculator using pointer variables?

Answer 1

Here's a simple C program to create a basic calculator using pointer variables:

#include <stdio.h>

void calculate(int *a, int *b, char op) {
    switch(op) {
        case '+': printf("Sum: %d\n", *a + *b); break;
        case '-': printf("Difference: %d\n", *a - *b); break;
        case '*': printf("Product: %d\n", *a * *b); break;
        case '/': 
            if (*b != 0)
                printf("Quotient: %d\n", *a / *b);
            else
                printf("Error: Division by zero.\n");
            break;
        default: printf("Invalid operator.\n");
    }
}

int main() {
    int num1, num2;
    char operator;
    printf("Enter two numbers: ");
    scanf("%d %d", &num1, &num2);
    printf("Enter operator (+, -, *, /): ");
    scanf(" %c", &operator);
    calculate(&num1, &num2, operator);
    return 0;
}

This program takes two integers and an operator from the user, then uses pointers to perform the corresponding arithmetic operation.