answersLogoWhite

0

the function (x),sory I can`t use the sign of the function because it is not available. the function of (x)=4x+4 is one to one function assume function(x1)= function(x2) then 4(x1)+4 =4(x2)+4 4(x1)=4(x2) (x1)=(x2) hence,the function is one to one

User Avatar

Wiki User

16y ago

What else can I help you with?

Related Questions

Can you define a function inside a function?

No. Functions should be defined separately. So you would not define a function within a function. You can define one function, and while defining another function, you can call the first function from its code.


Define the function of the preceding components in a network?

Define the function of the preceding components in a network?


Define finance function?

george way


Define string handling function?

Penis


How do you define power function without using operator?

using pow() function.. ..


Define parent function?

A parent function refers to the simplest function as regards sets of quadratic functions


How do you export a function?

To export a function in JavaScript, you can use the export keyword. For example, you can define a function and then export it directly: export function myFunction() { /* function code */ }. Alternatively, you can define the function first and then export it at the end of the file: function myFunction() { /* function code */ } export { myFunction };. This allows other modules to import and use the exported function.


Where is it possible to define a function in c?

yes you looser


Define formally Turing-Decidable Problem?

define function formally and using f(x) notation


What is the way by which you can make the user defined the size of the arrays?

By using the library function #define A[] we can define the size of arrays


How do you define fitness function in GAtool matlab?

x^2


Why we use function prototyping in c language?

You could just define the whole function before it is called, like this:void do_nothing(){}main(){do_nothing();}but if you define the function after it is called, the compiler will arrive at the function's calling before its actual definition. If you prototype your function earlier in the code than the function's call, the compiler will look for the function first.Hope I was able to help.