i think it means deca-octa hydrate..
The haudensaunee mean irguios
R mean reastate the question. A mean answer it. F mean for example. F mean for example. T mean this show that. RAFFT that what it mean in Ela
The two girls were very mean to me. This is a sentence containing the word mean.
what does it mean
mean
2c8h18 + 25o2--> 16co2 + 18h2o
it is -193 jk/g. or it is D.
The chemical equation for burning gasoline is: 2C8H18 + 25O2 -> 16CO2 + 18H2O.
2C8H18 + 25O2 -> 8CO2 + 18H2O No. I can see right off that you have 16 atoms of carbon on the reactant (left) side and only 8 atoms of carbon on the product (right) side. Let's see. 2C8H18 + 25O2 -> 16CO2 + 18H2O Now it is balanced.
Octane + Oxygen ----> Carbon dioxide + Water2 C8H18 + 25 O2 ----> 16 CO2 + 18H2O
This chemical equation represents the combustion of octane (C8H18) with oxygen (O2) to produce carbon dioxide (CO2) and water (H2O). The balanced equation is: 2C8H18 + 25O2 → 16CO2 + 18H2O This reaction is an example of complete combustion, where octane reacts with oxygen to form carbon dioxide and water.
This is a typical combustion reaction in that it involves a hydrocarbon reacting with oxygen. The products of combustion reactions are always carbon dioxide and water, just in varying quantities.
Alum is the old-fashioned name for potassium aluminum sulfate, and the formula is KAl(SO4)2. There will also be some water of crystallization attached to it, and there are some variations on that formula because there are different types of alum.
Gasoline is a complex mixture of hydrocarbons. When combusted in an engine, the main chemical reaction is the oxidation of these hydrocarbons to produce carbon dioxide, water, and heat. The balanced chemical equation for the combustion of a simple hydrocarbon such as octane (C8H18) in gasoline would be: 2C8H18 + 25O2 -> 16CO2 + 18H2O + heat.
The reaction is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O
The balanced chemical equation for the reaction C2H6 + O2 → CO2 + H2O is: 2 C2H6 + 7 O2 → 4 CO2 + 6 H2O
Reaction of octane combustion- 2C8H18+25O2= 16CO2+ 18H2O That mean from 228g octane (16*22.4dm3) = 358.4dm3 of CO2 is produced. {because volume of each mole is 22.4dm3} Now, from 10 kg of octane produced volume of CO2 is = (358.4*10000)/228 =(15719.298 dm3/1000)m3 =15.719 m3.