Ah, children, children. The answer is obvious if you look at old printings. Way back when, the letter was always written with two connected "U" shapes, hence the "double you" phonetics. Modern typesetters, then typewritters (and thence computers) changed the appearance of the letter. Why? Originally, probably to save costs/effort in making the mobil type used by the typesetters.
hope that helps... ;-)
If there was no 'W' then one might have had to use two U's to give the same sound. In Greek there is no 'W' and they use oui for the 'W' sound, so Wilkinson would be written starting with an oui. A double 'V' would give a totally different sound.
You can spell the letter 'w' as a word like this: 'double-u', or 'double-you'.
"W" has three syllables: dou-ble-u. As for why it is the only letter that has more than one syllable, I can only assume that it is because it was created by doubling the letter "U" (though it looks more like a double V if you ask me).
Because it looks similar to two letter 'U's.
h, j, q, v, w, x, y
The Latin alphabet IS the same as the English alphabet, with the exception of a few letters. The Modern Latin Alphabet is exactly the same as the English Alphabet. The Classic Latin alphabet is missing J, U, and W. There were no lower case letters at first, and K, Y and Z used only for writing words of Greek origin. The letters J, U and W were added to the alphabet at a later stage to write languages other than Latin. J is a variant of I, U is a variant of V, and W was introduced as a 'double-v' to make a distinction between the sounds we know as 'v' and 'w' which was unnecessary in Latin.
A "W" is called a "Double U" because U's used to be written like V's- and a W looks like two V's put together (W and VV look very simular)
before its actually a double u it looks like this UU but it acedently looked like a v Ww
The W descends from the Latin V, which was originally used for the u,v and w sounds. Julius was written ivlivs. After the 11th Century writers began differentiating the sounds, using the round u form for u and the v form for v sounds.A little later the W appeared, made from two "V"s (called "U"s), for the consonant u sound at the beginning of a word and the vocalic u sound at the end of a syllable.
Connection to these letters are U - L1, V - L2 and W - L
English uses the Latin alphabet of the Romans. However, this had no letter suitable for representing the phoneme /w/ which was used in Old English, though phonetically the sound represented by /v/ was quite close. In the 7th century scribes wrote uu for /w/; later they used the runic symbols known as wynn. European scribes had continued to write uu, and this usage returned to England with the Norman Conquest in 1066. Early printers sometimes used vv for lack of a w in their type. The name double-u recalls the former identity of u and v, which is also evident in a number of cognate words (flour/flower, guard/ward, suede/Swede, etc.).(Oxford Companion to the English Language)
yes. not sure of the proof though.
Dobbelve (double V)
I think its Wednesday. (V Vednesday) close the space between the two Vs and you have VV. In french W is called 'double V'
"Dub" is a nickname for the "W" (pronounced "double-U," hence--dub).
You can spell the letter 'w' as a word like this: 'double-u', or 'double-you'.
There are many letters with lines of symmetry. A, B, D, E, H, I, l, M, m, O, o, T, t, U, u, V, v, W, w, X, x, Y. A, B, D, E, H, I, l, M, m, O, o, T, t, U, u, V, v, W, w, X, x, Y.
Given an un-directed fully connected graph (there is an edge between every two vertices) with a weight function that has the triangle inequality. I.e., if (u,v), (v,w), (u,w) in E then w(u,v) + w(v,w) >= w(u,w). Do:find a minimum spanning treesplit each edge in the tree into two edges. Since all the degrees in the new graph are even, there is an Euler cycle in the graph. Find it.Whenever you can, cut corners. I.e., if the Euler path goes: v --> u --> v --> w, change it to go: v --> u --> w. From the assumptions on the graph we can only gain from this and we are guaranteed that there an edge u --> w.Ratio from the optimum:Note that the optimum (opt) path costs at most the value of the MST (just take one edge off the opt and you get a spanning tree). Since our path is at most twice the cost of the spanning tree we have a ratio of x2.