Each bit allows 21 combinations. Accordingly, n number of bits provide 2n combinations.
Therefore, 5 bits provide 25 = 32 combinations. # 00001 # 00010 # 00011 # 00100 # 00101 # 00110 # 00111 # ...
In a binary system, each bit can be either 0 or 1. Therefore, for 5 bits, the total number of combinations can be calculated as (2^5). This results in 32 different combinations, ranging from 00000 to 11111.
Each of the 5 digits has two possibilities. So the total number of possible combinations is2 x 2 x 2 x 2 x 2 = 32 .(Another way to ask the same question is: How many binary numbers can you write with 5 bits ?)
There are 5C3 = 5*4/(2*1) = 10 combinations
There are 5C3 = 10 combinations.
There are 5,461,512 such combinations.
There are 2*2*5 = 20 combinations.
Five. 5 bits gives 32 combinations. Early computers and telex machines used a five bit paper tape code. You use all blank (0) as tape leader and the other non-letter combinations for CR, LF, space, number shift and letter shift.
5 gb= 5*230 bits 88 mb= 88*220 bits Therefore if 88 mb is used out of 5 gb then = 5 gb - 88 mb bits are left = 5*2 30 bits - 88*220 bits = 220(5*210-88) bits = 220(5*1024-88) bits = 220*5032 bits = 5032 mb are left
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
27
40 bits or 5 byrtes
5 bits